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jeka57 [31]
3 years ago
11

(NH4)2CO3à NH3 + CO2 + H2O For this unbalanced chemical equation, what is the coefficient for carbon dioxide when the equation i

s balanced? A. 1 B. 2 C. 3 D. 4
Chemistry
2 answers:
nasty-shy [4]3 years ago
6 0

Answer:

The answer to your question is the letter A. 1

Explanation:

Data

Chemical reaction

                   (NH₄)₂CO₃  ⇒   NH₃  +  CO₂  + H₂O

               Reactants    Elements     Products

                      2            Nitrogen             1

                       1            Carbon                1

                       8           Hydrogen            5

                       3           Oxygen                3

This reaction is unbalanced

                   (NH₄)₂CO₃  ⇒   2NH₃  +  CO₂  + H₂O

               Reactants    Elements     Products

                      2            Nitrogen             2

                       1            Carbon                1

                       8           Hydrogen            8

                       3           Oxygen                3

Now, the reaction is balanced,

The coefficient for Carbon dioxide is 1

KIM [24]3 years ago
4 0

Answer:

The coefficient for carbon dioxide (CO2) is 1 (option A) is correct.

Explanation:

Step 1: The unbalanced equation

(NH4)2CO3 ⇒ NH3 + CO2 + H2O

Step 2: Balancing the equation

(NH4)2CO3 ⇒ NH3 + CO2 + H2O

On the left side, we have 2x N (in (NH4)2CO3), on the right side we have 1x N (in NH3). To balance the amount of N on both sides we have to multiply NH3 on the right side by 2. Now the equation is balanced.

(NH4)2CO3 ⇒ 2NH3 + CO2 + H2O

The coefficient for carbon dioxide (CO2) is 1 (option A) is correct.

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5. What concentration of acid must be added to change the pH of 1 mM phosphate buffer from 7.4 to 7.3 (pKas of the phosphate buf
mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and pK_{a} is as follows.

               pH = pK_{a} + log \frac{base}{acid}

where,     pH = 7.4 and pK_{a} = 7.21

As here, we can use the pK_{a} nearest to the desired pH.

So,      7.4 = 7.21 + log \frac{base}{acid}

             0.19 = log \frac{base}{acid}

            \frac{base}{acid} = 1.55

1 mM phosphate buffer means [HPO_{4}] + [H_{2}PO_{4}] = 1 mM

Therefore, the two equations will be as follows.

           \frac{HPO_{4}}{H_{2}PO_{4}} = 1.55 ............. (1)

  [HPO_{4}] + [H_{2}PO_{4}] = 1 mM ........... (2)        

Now, putting the value of [HPO_{4}] from equation (1) into equation (2) as follows.

             1.55[H_{2}PO_{4}] + [tex][H_{2}PO_{4}] = 1 mM

                        2.55 [H_{2}PO_{4}] = 1 mM

                             [H_{2}PO_{4}] = 0.392 mM

Putting the value of [H_{2}PO_{4}] in equation (1) we get the following.

                     0.392 mM + [HPO_{4}] = 1 mM

                          [HPO_{4}] = (1 - 0.392) mM

                              [HPO_{4}] = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0
3 years ago
The combustion of 135 mg of a hydrocarbon produces 440 mg of CO2 and 135 mg H2O. The molar mass of the hydrocarbon is 270 g/mol.
NeX [460]

Answer:

Molecular formula = C20H30

Explanation:

NB 440mg = 0.44g, 135mg= 0.135g

From the question, moles of CO2= 0.44/44= 0.01mol

Since 1 mol of CO2 contains 1mol of C, it implies mol of C = 0.01

Also from the question, moles of H2O = 0.135/18= 0.0075mole

Since 1 mol of H2O contains 2mol of H, it implies mol of H = 0.0075×2= 0.015 mol of H

To get the empirical formula, divide by smallest number of mole

Mol of C = 0.01/0.01=1

Mol of H = 0.015/0.01= 1.5

Multiply both by 2 to obtain a whole number

Mol of C =1×2 = 2

Mol of H= 1.5×2 = 3

Empirical formula= C2H3

[C2H3] not = 270

[ (2×12) + 3]n = 270

27n = 270

n=10

Molecular formula= [C2H3]10= C20H30

5 0
3 years ago
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lions [1.4K]

Answer:

A. bacteria

Explanation:

can i have brainlest?

8 0
3 years ago
A cylinder with a movable piston originally has a volume of 2805 mL and is filled with nitrogen to a pressure of 4.00
Sergio039 [100]

This problem is providing the initial volume and pressure of nitrogen in a piston-cylinder system and asks for the final pressure it will have when the volume increases. At the end, the answer turns out to be 2.90 atm.

<h3>Boyle's law</h3>

In chemistry, gas laws are used so as to understand the volume-pressure-temperature-moles behavior in ideal gases and relate different pairs of variables.

In this case, we focus on the Boyle's law as an inversely proportional relationship between both pressure and volume at constant both temperature and moles:

P_1V_1=P_2V_2

Thus, we solve for the final pressure by dividing both sides by V2:

P_2=\frac{P_1V_1}{V_2}

Hence, we plug in both the initial pressure and volume and final volume in order to calculate the final pressure:

P_2=\frac{2805mL*4.00atm}{3864mL}\\ \\P_2=2.90atm

Learn more about ideal gases: brainly.com/question/8711877

6 0
2 years ago
Which of the following is the best instrument to use to prepare a solution?
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The answer to your question would be D Volumetric Flask 
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