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Ugo [173]
2 years ago
6

How many molecules are in 0.25 grams of dinitrogen pentoxide?

Chemistry
2 answers:
ZanzabumX [31]2 years ago
7 0

Answer: 0.014\times 10^{23}molecules

Explanation: Moles can be calculated by using the formula:

\text{no of moles}=\frac{\text{given mass}}{\text{Molecular mass}}

\text{no of moles}=\frac{0.25g}{108g/mol}=0.002moles

1 mole of N_2O_5 contains =6.023\times 10^{23}molecules

0.002 mole of N_2O_5 contains =\frac{6.023\times 10^{23}}{1}\times 0.002=0.014\times 10^{23}molecules

Vesna [10]2 years ago
4 0
In order to get the answer, you have to know the formula of how to convert grams to mole and by that you can get the number of molecules.
The answer is 2 moles of N2O5. This is shown by the solution:
(0.25 g N2O5) (1 mol/ 108 g)=2.31 molecules
The answer is 2 molecules.
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1.) homogeneous mixtures

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5 0
3 years ago
The thin outer layer of Earth, called the crust, contains only 0.50 percent of Earth's total mass and yet is the source of almos
Rzqust [24]

Answer:

The mass of silicon in kilograms in Earth's crust is7.2729\times 10^{21} kg.

Explanation:

Mass of Earth =5.9\times 10^{21} tons

(1 ton= 2000 lb)

(1 lb =453.6 g)

1 ton = 2000 × 453.6 g =907,200 g

Mass of Earth =5.9\times 10^{21}\times 907,200 g=5.3524\times 10^{27} g

Percentage of earth crust = 0.50%

Mass of earth crust = M

0.50\%=\frac{M}{5.3524\times 10^{27}}\times 100

M=2.6762\times 10^{25} g

Percentage of the silicon in Earth's crust = 27.2 %

Mass of silicon in in Earth's crust = m

Si\%=\frac{m}{M}\times 100

27.2\%=\frac{m}{2.6762\times 10^{25} g}\times 100

m = 7.2792\times 10^{24} g=7.2729\times 10^{21} kg

1000 g = 1 kg

The mass of silicon in kilograms in Earth's crust is7.2729\times 10^{21} kg.

7 0
3 years ago
On the pH scale pure water has a pH of<br> A. 0<br> B. 7<br> C. 14
konstantin123 [22]

Answer:its b 7

Explanation:

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7 0
3 years ago
Read 2 more answers
1: At which temperature would a reaction withΔH = -102 kJ/mol, ΔS = -0.188 kJ/(mol×K) be spontaneous? 2: At which temperature wo
Naddik [55]

Answer:

1: At temperatures below 542.55 K

2: At temperatures above 660 K

Explanation:

Hello there!

In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:

\Delta G=\Delta H-T\Delta S

Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:

1:

0=\Delta H-T\Delta S\\\\T=\frac{-102kJ/mol}{-0.188kJ/mol-K} \\\\T=542.55K

It means that at temperatures lower than 542.55 K the reaction will be spontaneous.

2:

0=\Delta H-T\Delta S\\\\T=\frac{132kJ/mol}{0.200kJ/mol-K} \\\\T=660K

It means that at temperatures higher than 660 K the reaction will be spontaneous.

Best regards!

7 0
2 years ago
Who created the planetary model of the atom?
shtirl [24]
The answer is Rutherford.
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2 years ago
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