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Ugo [173]
2 years ago
6

How many molecules are in 0.25 grams of dinitrogen pentoxide?

Chemistry
2 answers:
ZanzabumX [31]2 years ago
7 0

Answer: 0.014\times 10^{23}molecules

Explanation: Moles can be calculated by using the formula:

\text{no of moles}=\frac{\text{given mass}}{\text{Molecular mass}}

\text{no of moles}=\frac{0.25g}{108g/mol}=0.002moles

1 mole of N_2O_5 contains =6.023\times 10^{23}molecules

0.002 mole of N_2O_5 contains =\frac{6.023\times 10^{23}}{1}\times 0.002=0.014\times 10^{23}molecules

Vesna [10]2 years ago
4 0
In order to get the answer, you have to know the formula of how to convert grams to mole and by that you can get the number of molecules.
The answer is 2 moles of N2O5. This is shown by the solution:
(0.25 g N2O5) (1 mol/ 108 g)=2.31 molecules
The answer is 2 molecules.
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jekas [21]

B) 1 and 3

it's the right answer

6 0
2 years ago
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If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what i
Ostrovityanka [42]

Consider the isomerization of butane with equilibrium constant is 2.5 .The system is originally at equilibrium with :

[butane]=1.0 M , [isobutane]=2.5 M

If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas?

Answer:

The equilibrium concentration of each gas:

[Butane] = 1.14 M

[isobutane] = 2.86 M

Explanation:

Butane  ⇄  Isobutane

At equilibrium

1.0 M               2.5 M

After addition of 0.50 M of butane:

(1.0 + 0.50) M               -

After equilibrium reestablishes:

(1.50-x)M            (2.5+x)

The equilibrium expression will wriiten as:

K_c=\frac{[Isobutane]}{[Butane]}

2.5=\frac{2.5+x}{(1.50-x)}

x = 0.36 M

The equilibrium concentration of each gas:

[Butane]= (1.50-x) = 1.50 M - 0.36M = 1.14 M

[isobutane]= (2.5+x) = 2.50 M + 0.36 M = 2.86 M

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3 years ago
Titration Lab Day 2 Data Sheet help?
igomit [66]
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2 years ago
Calculate the Ph of:
andrey2020 [161]

Answer:

pH= 3.82

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3 years ago
Based on the three formulas shown, use one of them to solve for the purple yellow and red box and explain how you did it.
zysi [14]

P = 11.133 atm (purple)

T = -236.733 °C(yellow)

n = 0.174 mol(red)

<h3>Further explanation  </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:  

  • Boyle's law at constant T, P = 1 / V  
  • Charles's law, at constant P, V = T  
  • Avogadro's law, at constant P and T, V = n  

So that the three laws can be combined into a single gas equation, the ideal gas equation  

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

To choose the formula used, we refer to the data provided

Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT

  • Purple box

T= 10 +273.15 = 373.15 K

V=5.5 L

n=2 mol

\tt P=\dfrac{nRT}{V}\\\\P=\dfrac{2\times 0.08205\times 373.15}{5.5}\\\\P=11.133~atm

  • Yellow box

V=8.3 L

P=1.8 atm

n=5 mol

\tt T=\dfrac{PV}{nR}\\\\T=\dfrac{1.8\times 8.3}{5\times 0.08205}\\\\T=36.42~K=-236.733^oC

  • Red box

T = 12 + 273.15 = 285.15 K

V=3.4 L

P=1.2 atm

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.2\times 3.4}{0.08205\times 285.15}\\\\n=0.174~mol

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2 years ago
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