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Natali5045456 [20]
2 years ago
11

What dose plasma come from

Chemistry
2 answers:
steposvetlana [31]2 years ago
7 0
Plasma is the clear portion of blood after the red and white blood cell, celular components are removed
lukranit [14]2 years ago
3 0

blood

Explanation:

it is the liquid part of blood used to flow through the human body

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What is the relationship between the internal energy of a substance and its particle movement?
ss7ja [257]

Answer: The closeness, arrangement and motion of the particles in a substance change when it changes state. Materials are a store of internal energy , due to the motion of particles and the chemical bonds between them. When a substance is heated, its internal energy increases: the movement of its particles increases.

Explanation:

6 0
3 years ago
What is the molariity of a 50.0 mL aqueous solution containing 10.0 grams of acetic acid, CH3COOH
rosijanka [135]

Answer:

The molarity is 1.26

Explanation:

5 0
2 years ago
Read 2 more answers
Does anybody know how to do this if so please help !
Viktor [21]

Answer:

add x to 7 and divide by 3

Explanation:

easier formula

3 0
2 years ago
In the balanced reaction below, what is the mole ratio comparing iron (Fe) and oxygen gas (O2)?
zepelin [54]

The given balanced reaction is,

4Fe(s) + 3O_{2}(g) --->2Fe_{2}O_{3} (s)

The stoichiometric coefficients of each element or compound represents the number of moles of that element or compound required for the complete reaction to take place.

The mole ratios of different products and reactants will be:

\frac{Fe}{O_{2}} = \frac{4 mol Fe}{3 mol O_{2}}

\frac{Fe}{Fe_{2}O_{3}} = \frac{4 mol Fe}{2 Fe_{2}O_{3}}

\frac{O_{2}}{Fe_{2}O_{3}} =\frac{3 mol O_{2}}{2molFe_{2}O_{3}}

So the mole ratio comparing iron (Fe) and oxygen gas (O_{2}) is

4 : 3

5 0
3 years ago
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How many grams of KCIO3 are needed to produce 5.00 of O2 at STP?
Arlecino [84]
2KClO₃ → 2KCl + 3O₂

mole ratio of KClO₃ to O₂ is 2 : 3

∴ if moles of O₂ = 5 mol

then moles of KClO₃ = \frac{5 mol   *   2}{3}

                            = 3.33 mol


Mass of KClO₃ needed = mol of KClO₃ × molar mass of KClO₃

                                      = 3.33 mol × ((39 × 1) + (35.5 × 1) + (16 × 3) g/mol

                                      = 407.93 g
6 0
2 years ago
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