<h3>What I think is : The protons are present at the centre of the atom with rotating electrons around it so when it is rubbed by fur the electrons get passed from the ebonite rod to the fur leaving the rod negatively charged</h3>

<h2>Hope this helps you ❤️</h2>

<h2>Mark me as brainliest ❤️</h2>

6 0

3 years ago

Determine the mass of 2.94 x 10^34 molecules of decane

djyliett [7]

2.94
×
10
24
⋅
molecules
6.022
×
10
23
⋅
molecules
⋅
mol
−
1
×
142.3
⋅
g
⋅
mol
−
1
≅
700
⋅
g

6 0

4 years ago

Consider stoichiometric combustion of gasoline and air. Assume a full tank of gasoline holds 50 L (approximately 13.2 gallons),

Inessa05 [86]

Answer:

520 kg

Explanation:

Let's consider the combustion of isooctane.

C₈H₁₈(l) + 12.5 O₂(g) → 8 CO₂(g) + 9 H₂O(l)

We can establish the following relations:

1 mL of C₈H₁₈ has a mass of 0.690 g (ρ = 0.690 g/mL).
The molar mass of C₈H₁₈ is 114.22 g/mol.
The molar ratio of C₈H₁₈ to O₂ is 1:12.5.
The mole fraction of O₂ in air is 0.21.
The molar mass of air is 28.96 g/mol.

50 L of isooctane require the following mass of air.

$50 \times 10^{3}mLC_{8}H_{18}.\frac{0.690gC_{8}H_{18}}{1mLC_{8}H_{18}} .\frac{1molC_{8}H_{18}}{114.22gC_{8}H_{18}} .\frac{12.5molO_{2}}{1molC_{8}H_{18}} .\frac{1molAir}{0.21molO_{2}} .\frac{28.96 \times 10^{-3}kgAir}{1molAir} =520kgAir$

5 0

4 years ago