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skad [1K]
2 years ago
15

The intensity of light from a central source varies inversely as the square of the distance. If you lived on a planet only half

as far from the Sun as our Earth, how would the intensity compare with that on Earth?
Physics
1 answer:
sertanlavr [38]2 years ago
5 0

Answer:

the intensity will be 4 times that of the earth.

Explanation:

let us assume the following:

intensity of light on earth =J

distance of earth from sun = d

intensity of light on other planet = K

distance of other planet from sun = \frac{d}{2} (from the question, the planet is half as far from the sun as earth)

from the question the intensity is inversely proportional to the square of the distance, hence

  • intensity on earth : J = \frac{1}{d^{2} }

        Jd^{2} = 1 ... equation 1

  • intensity on other planet : K =  \frac{1}{(\frac{d}{2}) ^{2} }  (the planet is half as far from the sun as earth)

        K(\frac{d}{2}) ^{2} = 1 ....equation 2

  • equating both equation 1 and 2 we have

       Jd^{2} = K(\frac{d}{2}) ^{2}

       Jd^{2} = K\frac{d^{2}}{4}

       J = \frac{K}{4}

        K = 4J

       intensity of light on other planet (K) = 4 times intensity of light on earth (J)

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2 years ago
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What is the torque τa about axis a due to the force f⃗ ? express the torque about axis a at cartesian coordinates (0,0)?
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Answer:

\tau_a = F a sin \theta

Explanation:

The torque of a force is given by:

\tau = F d sin \theta

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\theta is the angle between the direction of the force and d

In this problem, we have:

F, the force

a, the distance of application of the force from the centre (0,0)

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5 0
3 years ago
A ray of light in glass strikes a water-glass interface at an angle of incidence equal to one-half the critical angle for that i
fomenos

Answer:

Explanation:

There will not be any internal reflection . it will be only refraction

critical angle = θ

Sinθ = 1 / μg

μg = 1.43 / 1.33 =

Sinθ = 1.33 / 1.43

= .93

θ = 68.44

angle of incidence i = 68.44 / 2

= 34.22

Sin i / Sin r = μw = 1.33 / 1.43  

= .93

sin 34.22  / sinθ₁ = .93 , θ₁ is angle of refraction.

sinθ₁ = sin 34.22 / .93

= .5623 / .93

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2 years ago
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Answer:

C. \frac{3F}{8}

Explanation:

Let initial charges on both spheres be,q

F=\frac{Kq^2}{d^2}   \ \ \  \ \ \  \ \ \  \ \_i

When the sphere C is touched by A, the final charges on both will be,\frac{q}{2}

#Now, when C is touched by B, the final charges on both of them will be:

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Now the force between A and B is calculated as:

F\prime=\frac{k\times\frac{q}{2}\times \frac{3q}{4}}{d^2}\\F\prime=\frac{3F}{8}

Hence the electrostatic force becomes 3F/8

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2 years ago
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