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3 years ago

Sequences of Transformations

Mathematics

2 answers:

kipiarov [429]3 years ago

4 0

The answer is 3 because flipped it’s the same but then cutting it in half is 3

sukhopar [10]3 years ago

3 0

Answer:

Step-by-step explanation:

Oooo nice correct

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Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .

Hope this wasn't too confusing! I'll answer any questions.

8 0

2 years ago

Read 2 more answers

Solve for n.<br> n^2–15n–16=0

Fofino [41]

N = {15 +- root of ( 225 + 64) } / 2
= {15 +- root of 289 } / 24
= 15 + 17 } / 2 or { 15 -17 } /2
= 16 or -1

5 0

3 years ago

Can x in f(x) be replaced by another letter? For example f(a);Would that be the same thing?

Murljashka [212]

Answer:

Yes

Step-by-step explanation:

X is just an unknown variable which can be substituted as another variating condition. I.E Function of x can be written as Function of a. If no other condition is present.

5 0

3 years ago

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Please help asap 50 pts

adoni [48]

The answer is d

hope this helped!!

p.s. if you found this helpful please mark it as brainliest! it would mean a lot to me, thanks!

3 0

3 years ago

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Sladkaya [172]

Your answer is a your welcome

4 0

2 years ago