Answer:
The answer is "
".
Explanation:
Overall delivered volume ![= [(49.06 \pm 0.05) + (1.77 \pm 0.05)]\ mL](https://tex.z-dn.net/?f=%3D%20%5B%2849.06%20%5Cpm%200.05%29%20%2B%20%281.77%20%5Cpm%200.05%29%5D%5C%20mL)
Its blank solution without any of the required analysis
Compute the volume of the endpoint as follows:
Formula:


therefore,
absolute uncertainty

The Endpoint volume 

Therefore, the volume of the endpoint adjusted for the blank is:

The initial volume of the gas is obtained as 11.02 L.
<h3>What is the initial volume?</h3>
The work done can be obtained from the use of the formula;
W = PΔV
W = work done on the gas
P = pressure of the gas
ΔV = Change in volume
Now we can see that;
Internal energy = 127.5 J or 1.26 Latm
Heat lost = 34.7 J or 0.34 Latm
We now have;
-1.26 = 0.34 - 0.900(12.80 - V1)
-1.26 = 0.34 - 11.52 + 0.9V1
-1.26 + 11.18 = 0.9V1
V1 = -1.26 + 11.18 / 0.9
V1 = 11.02 L
Learn more about work done:brainly.com/question/13031096
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Mass percentage of sodium chloride(NaCl) in ocean waters = 3.5 %
That means 3.5 g sodium chloride(NaCl) is present for every 100 g of ocean water.
The given mass of sodium chloride(NaCl) is 45.8 g
Calculating the mass of ocean waters that would contain 45.8 g sodium chloride(NaCl):

= 1309 g ocean water
Therefore, 45.8 g sodium chloride is present in 1309 g ocean water.
Hello!
Given the density of mercury being 13.57 g/mL, and the mass of 52 kilograms, we need to find the volume.
To find the volume, we need to divide mass by density (V = m/d).
Notice that you are given 52 kilograms, but not grams. To convert kilograms to grams, you need to multiply it by 1000.
52 x 1000 = 52000 grams
With the correct measurements, we can find the volume.
V = 52000 grams / 13.56 grams/milliliter
V ≈ 3834.80826
Therefore, the volume of the mercury is about 3,834.81 mL.
Inquiring, which comes from the word inquiry which means, "an act of asking a question". In science, the first part of the scientific method is asking questions about the world around you and then after that, conducting experiments to get answers.