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erastova [34]
3 years ago
15

2. How many moles of fluorine are required to produce 12.0 grams of

Chemistry
1 answer:
LuckyWell [14K]3 years ago
7 0

Answer:

0.0984mol of F2

Explanation:

The equation for the reaction is given below:

Kr + F2 → KrF2

Let us convert 12g of KrF2 to mole. This is illustrated below

Molar Mass of KrF2 = 84 + (2x19) = 84 + 38 = 122g/mol

Mass of KrF2 = 12g

Number of mole = Mass /Molar Mass

Number of mole of KrF2 = 12/122 = 0.0984mol

From the equation,

1mole of F2 produced 1mole of KrF2.

Therefore 0.0984mol of F2 will produce 0.0984mol of KrF2

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Suppose a solution is described as concentrated. Which of the following statements can be concluded? Select the correct answer b
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Answer:

  • last option: none of<u> the above.</u>

Explanation:

Describing a solution as<em> concentrated</em> tells that the solution has a relative large concentration, but it is a qualitative description, not a quantitative one, so this does not tell really how concentrated the solution is. This is, the term concentrated is a kind of vague; it just lets you know that the solution is not very diluted, but, as said initially, that there is a relative large amount (concentration) of solute.

One conclusion, of course, is that <u>the solute is soluble</u>: else the solution were not concentrated.

On the other hand, the terms saturated and <em>supersaturated</em> to define a solution are specific.

A saturated solution has all the solute that certain amount of solvent can contain, at a given temperature. A <u>supersaturated solution has more solute dissolved than the saturated solution</u> at the same temperature; superstaturation is a very unstable condition.

From above, there is no way that you can conclude whether a solution is supersaturated or not from the statement that a solution is concentrated, so the answer is<u> none of the above</u>.

5 0
3 years ago
What are the units of molar mass?<br> O A Lg<br> B. g/mol<br> O C. g/L<br> D. mol/g
kondaur [170]
D I think hope this helps
6 0
3 years ago
Read 2 more answers
You are given the reaction Cu + HNO3 → Cu(NO3)2 + NO + H2O. Half-reactions: First: 3 upper C u right arrow 3 upper C u superscri
nexus9112 [7]

Answer: It is the first one. First: 3 upper C u right arrow 3 Upper C u superscript 2 plus, plus 6 e superscript minus. Second: 2 upper N superscript 5 plus, plus 6 e superscript minus right arrow 2 upper N superscript 2 plus.

Explanation:

Correct

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3 years ago
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. If Kc is the equilibrium constant for a forward reaction, 2 A⇌ B, what is Kc' for the reaction 4 A⇌ 2B?
olganol [36]

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Explanation:

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3 years ago
Sodium is much more apt to exist as a cation than chlorine because:
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Answer:

(D) chlorine has a greater ionization energy than sodium

Explanation:

Sodium is the element of the group 1 and period 3 which means that the valence electronic configuration is [Ne]3s^1.

Chlorine is the element of the group 17 and period 3 which means that the valence electronic configuration is [Ne]3s^23p^5.

Ionization energy is the minimum amount of energy which is required to knock out the loosely bound valence electron from the isolated gaseous atom.

<u>Thus, removal of one electron in sodium is easy as it will gain noble gas configuration and become stable. But this case does not exist in chlorine and hence, chlorine has a greater ionization energy than sodium.</u>

So,

Sodium is much more apt to exist as a cation than chlorine because chlorine has a greater ionization energy than sodium.

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3 years ago
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