All categories

3 years ago

Natural atom of the same element may have the same _________?

Chemistry

2 answers:

grigory [225]3 years ago

5 0

Answer: i think it is c

Explanation: i checked my textbook.

Minchanka [31]3 years ago

4 0

Answer:B

Explanation:

You might be interested in

For a certain chemical reaction, the standard Gibbs free energy of reaction at 30.0 °C is 110. kJ. Calculate the equlilibriunm c

mestny [16]

Answer:

Explanation:

The equation that relates standard Gibbs free energy, ΔG, with equilibrium constant, K, is:

ΔG = -RT ln K

<em>Where R is gas constant, 8.314J/molK, and T is absolute temperatue (30.0°C + 273.15 = 303.15K).</em>

<em />

Replacing (110kJ = 110000J):

110000J/mol = -8.314J/molK*303.15K ln K

-43.644 = lnK

1.11x10⁻¹⁹ = K

<em />

7 0

3 years ago

PLEASEEEE HELP MEEEEE

fiasKO [112]

Answer:

3.82 x 10²¹ molecules As₂O₃

Explanation:

To find the amount of molecules arsenic (III) oxide (As₂O₃), you need to (1) convert kg to lbs, then (2) convert g As₂O₃ to moles As₂O₃ (via molar mass), and then (3) convert moles to molecules (via Avogadro's number).

1 kilogram = 2.2 lb

Molar Mass (As₂O₃): 2(74.992 g/mol) + 3(15.998 g/mol)

Molar Mass (As₂O₃): 197.978 g/mol

Avogadro's Number:

6.022 x 10²³ molecules = 1 mole

0.0146 g As₂O₃ 1 kg 189 lb
------------------------ x --------------- x ------------------ x ................
1 kg 2.2 lb

1 mole 6.022 x 10²³ molecules
x ------------------ x --------------------------------------- = 3.82 x 10²¹ molecules As₂O₃
197.978 g 1 mole

6 0

2 years ago

Read 2 more answers

Consider the following system at equilibrium where H° = 111 kJ/mol, and Kc = 6.30, at 723 K.

Rashid [163]

Answer:

1) The value of Kc:

C. remains the same.

2) The value of Qc:

A. is greater than Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium.

4) The concentration of N2 will:

B. decrease.

Explanation:

Hello,

In this case, by means of the Le Chatelier's principle which is based on the shift a chemical reaction could have under some modifications, we have:

1) The value of Kc:

C. remains the same, since it just depend the reaction's thermodynamics as it is computed via:

$ln(K)=\frac{\Delta _RG}{RT}$

2) The value of Qc:

A. is greater than Kc, since the reaction quotient is:

$Qc=\frac{[N_2][H_2]^3}{[NH_3]^2}$

Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium, since ammonia was withdrawn and should be regenerated to reach the equilibrium.

4) The concentration of N2 will:

B. decrease, since less reactant is forming the products.

Best regards.

8 0

3 years ago

Read 2 more answers

Which intermolecular forces increase rapidly with increasing molecular size?

blondinia [14]

LONDON DISPERSION FORCES

8 0

3 years ago

Using ethanol and sodium or potassium cyanide as the sources of the carbon atoms, along with any necessary inorganic reagents, s

11Alexandr11 [23.1K]

Answer:

Please see attachment

Explanation:

Please see attachment

3 0

3 years ago