Answer:
A
Explanation:
Since the new moon is behind the earth, It is sun, earth, moon
Answer:
Ka = 3.50x10⁻⁴
Explanation:
First, we need to convert the unit of 3.60 g/L to mol/L:
The reaction dissociation of aspirin in water is:
C₉H₈O₄ + H₂O ⇄ C₉H₇O₄⁻ + H₃O⁺
0.02 - x x x
The constant of the above reaction is:
![Ka = \frac{[C_{9}H_{7}O_{4}^{-}][H_{3}O^{+}]}{[C_{9}H_{8}O_{4}]}](https://tex.z-dn.net/?f=%20Ka%20%3D%20%5Cfrac%7B%5BC_%7B9%7DH_%7B7%7DO_%7B4%7D%5E%7B-%7D%5D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BC_%7B9%7DH_%7B8%7DO_%7B4%7D%5D%7D%20)
To find Ka we need to find the value of x. We know that pH = 2.6 so:
![pH = -log[H_{3}O^{+}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20)
![x = 2.51 \cdot 10^{-3} M = [H_{3}O^{+}] = [C_{9}H_{7}O_{4}^{-}]](https://tex.z-dn.net/?f=%20x%20%3D%202.51%20%5Ccdot%2010%5E%7B-3%7D%20M%20%3D%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%20%3D%20%5BC_%7B9%7DH_%7B7%7DO_%7B4%7D%5E%7B-%7D%5D%20)
Now, the concentration of C₉H₈O₄ is:
Finally, Ka is:
![Ka = \frac{[C_{9}H_{7}O_{4}^{-}][H_{3}O^{+}]}{[C_{9}H_{8}O_{4}]} = \frac{(2.51 \cdot 10^{-3})^{2}}{0.018} = 3.50 \cdot 10^{-4}](https://tex.z-dn.net/?f=%20Ka%20%3D%20%5Cfrac%7B%5BC_%7B9%7DH_%7B7%7DO_%7B4%7D%5E%7B-%7D%5D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BC_%7B9%7DH_%7B8%7DO_%7B4%7D%5D%7D%20%3D%20%5Cfrac%7B%282.51%20%5Ccdot%2010%5E%7B-3%7D%29%5E%7B2%7D%7D%7B0.018%7D%20%3D%203.50%20%5Ccdot%2010%5E%7B-4%7D%20)
Therefore, the Ka of aspirin is 3.50x10⁻⁴.
I hope it helps you!
Vguttfvjhhutdxcbhyyyhhhhhhh HD jv bc HD g G G HD F G G f ft
Answer:
It reads as follows: 0.5 moles of solute per liter of solution.
Explanation:
Molarity is the most frequent way of expressing the concentration of solutions in chemistry, and it indicates the number of moles of solute dissolved per liter of solution; is represented by the letter M.
Answer: 72L of 30% and 128L of 80%
You can determine the weight of the acid by multiplying the concentration with the volume. Let say v1 is the volume of 30% solution needed and v2 is the volume of 80% solution.
The weight of acid from the used solution should be equal to the product. You can get this equation
final solution= solution1 + solution2
200l * 62%= v1 * 30% + v2*80%
124L= 0.3v1 + 0.8v2
124L- 0.3v1= 0.8v2
v2=155L- 0.375v1
The total volume of both should be 200l. If you use the previous equation, you can calculate:
v1+v2=200L
v1+ (155L- 0.375v1)= 200L
0.625v1= 200L - 155L
v1= 45/ 0.625= 72L
v1+v2=200L
v2= 200L- 72L= 128L
