When two 1s hydrogen atoms combine to form h2, the bond formed is:?

1 answer:

5 0

H2 is a covalent bond. Each hydrogen atom shares its single electron to the other, so each hydrogen has two valence electrons (full outer shell).

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Balanced nuclear equation forces the alpha decay Po-210

Serjik [45]

Answer:

$_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}$

Explanation:

Your unbalanced nuclear equation is:

$_{84}^{210}\text{Po} \longrightarrow \, _{x}^{y}\text{Z} + \, _{2}^{4}\text{He}$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.

Then

84 = x + 2, so x = 84 - 2 = 82

210 = y + 4, so y = 210 - 4 = 206

Element 82 is lead, so the nuclear equation becomes

$_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}$

8 0

3 years ago

What is the pH of a solution with an [H+] = 4.73x10^-7 M

Mice21 [21]

Answer:

The answer to your question is pH = 6.3

Explanation:

Data

pH = ?

[H⁺] = 4.73 x 10⁻⁷ M

pH is the measure of the concentration of [H⁺]. pH measures the acidity of the solution. If the value of pH is between 0 and 6.9, the solution is an acid. If the pH is 7.0 the solution is neutral and if the pH is between 7.1 and 14, the solution is an alkali.

Formula

pH = -log[H⁺]

Substitution

pH = -log[4.73 x 10⁻⁷]

-Simplification

pH = - (-6.3)

-Result

pH = 6.3

6 0

3 years ago

calcium reacts with fluorine to produce calcium fluoride. how does oxidation and reduction take place in this reaction?

Assoli18 [71]

The oxidation is occurring on Calcium ions as it release one electron and reduction will be occurring on fluorine ion as it accepts one electron.

<u>Explanation:</u>

An element will undergo oxidation and form a positive ion on releasing one or more electrons from its valence shell. While reduction is occurred in a chemical reaction, then the element will be forming a negative ion with the acceptance of one or more electrons in its valence shell.

So in the given process of calcium fluoride, the one electron from the valence shell of calcium will be released making it as $c a^{+}$ ions and this is termed as oxidation process. This one electron will be getting accepted by the fluorine ion and thus it will convert to $F^{-}$ ions. This process of acceptance of electrons is termed as reduction.