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lakkis [162]
4 years ago
13

When two 1s hydrogen atoms combine to form h2, the bond formed is:?

Chemistry
1 answer:
Tanya [424]4 years ago
5 0
H2 is a covalent bond. Each hydrogen atom shares its single electron to the other, so each hydrogen has two valence electrons (full outer shell).
You might be interested in
3Ba+Al2(SO4)3 -->2Al+3BaSO4,
daser333 [38]

Answer:

13.5 * 10^-2 g

Explanation:

What we know:

Balanced Equation: 3Ba+Al2(SO4)3 -->2Al+3BaSO4,

Grams of Ba: 1

Grams of Al2(SO4)3: 1.8g

Calculate the # of moles of Ba and Al2(SO4)3:

1g Ba/137.3 = 7.3 *10^-3 mol Ba

1.8g Al2(SO4)3/ 342 = 5.3 *10^-3 mol Al2(SO4)3

Find the limiting reactant:

Ba has a coefficient of 3 in the balanced equation, so we divide the # of moles of Ba by 3 to get... 7.3 *10^-3 mol Ba/3 = 2.43 *10^-3

Al2(SO4)3 has a coefficient of 1, so if we divide by 1, we get the same number of 5.3 *10^-3

2.43 *10^-3 is smaller than 5.3 *10^-3, therefore Ba is the limiting reactant.

finally, we just find the number of moles of Al

The ratio of Al to Ba is 2:3 so...

7.3 * 10^-3 * (2/3) = 5 *10^-3 mol Al

CONVERT TO GRAMS

5 *10^-3 mol Al  * 27 = 13.5 * 10^-2 g

<u>Hope that was helpful! </u>

6 0
2 years ago
How many different isomers can be derived from ethylene if two hydrogen atoms are replaced by a fl uorine atom and a chlorine at
svp [43]
Answer:
             THREE<span> different isomers can be derived from ethylene if two hydrogen atoms are replaced by a fl uorine atom and a chlorine atom.

Explanation:
                   When two Hydrogen atoms in ethylene (C</span>₂H₄) are replaced with Fluorine and Chlorine atom then the new molecular formula is C₂H₂FCl.
                    Compounds having same Molecular formula but different structural formula are called as Isomers.
                     First Isomer of C₂H₂FCl is 1-chloro-1-fluoroethene, in which F and Cl at geminal position (attached to same Carbon atom).
                     Other two Isomers are Geometrical Isomers of 1-chloro-2-fluoroethene, in which F and Cl at different carbon atom and having different position is space. The one in which both F and Cl at opposite side forms (<em>trans</em>)-1-chloro-2-fluoroethene and the one in which both are in same side is called as (<em>cis</em>)-1-chloro-2-fluoroethene.

8 0
3 years ago
Electromagnetic waves with the shortest wavelengths and highest frequencies are called​
Feliz [49]

Gamma rays

Explanation:

Every member of the electromagnetic radiation has commensurate amount of energy, wavelength and frequencies.

The electromagnetic waves with the shortest wavelengths and the highest frequencies are the gamma rays.

  • Gamma rays also are the most energetic electromagnetic radiation.
  • The short wavelength of gamma rays suggests that more waves passes with times.
  • It's high frequency shows that a high amount of wave passes through a point at each passing of time.
  • These factors combines to give its high energy. Energy of an electromagnetic radiation is a factor of its wavelength and frequency.
  • Gamma rays are ionizing radiations which causes ionization of gas molecules.

Learn more:

Radiation brainly.com/question/10726711

#learnwithBrainly

4 0
3 years ago
A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from
sweet-ann [11.9K]

Answer:

T_i~=163.1 ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

<u>Initial temperature of gold= Unknow</u>

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the <u>heat equation</u>:

Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT

Q_A_u=m_A_u*Cp_A_u*deltaT

We can relate these equations if we take into account that <u>all heat of gold is transfer to the water</u>, so:

m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT

Now we can <u>put the values into the equation</u>:

60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)

Now we can <u>solve for the initial temperature of gold</u>, so:

T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20

T_i~=163.1 ºC

I hope it helps!

5 0
3 years ago
Where all broken angeles but just because you got broken wings dont mean you can't fly. &lt;3
Brut [27]
Make more poems      +                        pleeeeeeees :3
6 0
3 years ago
Read 2 more answers
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