Hybrid = having one recessive and one dominant allele
This means that all of the flowers must have the genotype Bb.
Knowing this, let's make a Punnet Square.
As you can see, 3 of these are going to have the dominant trait and 1 is going to have the recessive trait. This corresponds to our 3:1 in our question, meaning that the black seeds must be dominant and the brown ones recessive.
Because they are dominant, the genotype for black seeds could be
BB <em /><em>or</em>
Bb.
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Answer:
B. 0.42
Explanation:
Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1
According to the given information, the frequency of one allele in the population is= 0.7
This means that the frequency of the other allele would be= 1-0.7 = 0.3
Frequency of heterozygote in the population =2pq = 2 x 0.7 x 0.3 = 0.42
Answer:
Generation of an action potential in the neuron.
Stimulation of Ca2+ entry into the neuron
Release of acetylcholine into the synapse
Depolarization of the muscle fiber membrane
Explanation:
The following events takes place in the vertebrate neuromuscular junction
a) Nerve Action Potential - Action potential reaches the axon terminal
b) Entry of calcium ion - The calcium ion reaches the axon terminal and enter into the presynaptic terminus after which the Synaptic vesicles fuse with the membrane of axon terminal
c) Releasing of Arch Quanta - Acetylcholine is released into synaptic cleft which then binds to the receptor sites on motor end plate
d) The Na+/K+ channels opens and Motor end plate becomes depolarized.
<span>Choice (a) is the most correct. Fish must excrete large quantities of water as a way of keeping the homeostasis in their cells. Otherwise, the water levels in the cell could become too high and the cells would likely rupture, leading to the death of the organism.</span>