Answer:
is personally responsible for all partnership debts
Explanation:
COMPLETE QUESTION
A general partner:
is personally responsible for all partnership debts. has no say over a firm's daily operations. faces double taxation whereas a limited partner does not. has a maximum loss equal to his or her equity investment. receives a salary in lieu of a portion of the profits.
EXPLANATION
A general partner can be regarded as a person that joins with another person or join with more than one other person to form a business. A general partner is responsible for the actions that is been taken in the business, He or she is liable personally for all the debts as well as obligations in the business and can bind the business legally. It should be noted that A general partner is personally responsible for all partnership debts.
Answer:
a. Ted gets the hut; Sadie gets the rest.
Explanation:
Since Ted placed a much more higher priority on the hut by assigning it 35 points more than all other items, and Sadie placed a very low priority on the hut by assigning it 10 points when compared to all other items, it shows Ted is ready to let go of other items just to have the hut, and Sadie is ready to let go of the hut to have the other item. Hence, the "Ted gets the hut, Sadie gets the rest" splits is efficient.
The correct answers are the following; corporate site and
commerce site.
corporate site is defined as a website of the business or corporate by which it
differs from portal sites and e-commerce sites.
commerce site is a website designed for having to promote goods and services.
The filter that can be used to find a specific project when in the work area is: Project name.
<h3>Project Filter</h3>
When looking or searching for a particular project that meet your requirement in a work area, in order to find the project the best thing to do is to include the following filter as it will enables you to find the project you are looking for;
- Project name
- Due date
- Template name
- Team member
Therefore the filter that can be used to find a specific project when in the work area is: Project name.
Learn more about project filter here:brainly.com/question/23643337
#SPJ11
Answer: (a) $197,500
(b) $ 189,500
Explanation:
Given : The marginal cost function : 
To find the cost function, we need to integrate the above function with respect to x.
Now, the additional cost incurred in dollars when production is increased from 100 units to 150 units will be:-
![\int^{150}_{100}\ C'(x)\ dx\\\\=\int^{150}_{100} (4000-0.4x)\ dx\\\\=[4000x-\dfrac{0.4x^2}{2}]^{150}_{100}\\\\=[4000(150)-\dfrac{0.4(150)^2}{2}-4000(100)+\dfrac{0.4(100)^2}{2}]\\\\=[600000-4500-400000+2000]\\\\=197500](https://tex.z-dn.net/?f=%5Cint%5E%7B150%7D_%7B100%7D%5C%20C%27%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B150%7D_%7B100%7D%20%284000-0.4x%29%5C%20dx%5C%5C%5C%5C%3D%5B4000x-%5Cdfrac%7B0.4x%5E2%7D%7B2%7D%5D%5E%7B150%7D_%7B100%7D%5C%5C%5C%5C%3D%5B4000%28150%29-%5Cdfrac%7B0.4%28150%29%5E2%7D%7B2%7D-4000%28100%29%2B%5Cdfrac%7B0.4%28100%29%5E2%7D%7B2%7D%5D%5C%5C%5C%5C%3D%5B600000-4500-400000%2B2000%5D%5C%5C%5C%5C%3D197500)
Hence, the additional cost incurred in dollars when production is increased from 100 units to 150 units= $197,500
Similarly, the additional cost incurred in dollars when production is increased from 500 units to 550 units :-
![\int^{550}_{500}\ C'(x)\ dx\\\\=\int^{550}_{500} (4000-0.4x)\ dx\\\\=[4000x-\dfrac{0.4x^2}{2}]^{550}_{500}\\\\=[4000(550)-\dfrac{0.4(550)^2}{2}-4000(500)+\dfrac{0.4(500)^2}{2}]\\\\=[2200000-60500-2000000+50000]\\\\=189,500](https://tex.z-dn.net/?f=%5Cint%5E%7B550%7D_%7B500%7D%5C%20C%27%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B550%7D_%7B500%7D%20%284000-0.4x%29%5C%20dx%5C%5C%5C%5C%3D%5B4000x-%5Cdfrac%7B0.4x%5E2%7D%7B2%7D%5D%5E%7B550%7D_%7B500%7D%5C%5C%5C%5C%3D%5B4000%28550%29-%5Cdfrac%7B0.4%28550%29%5E2%7D%7B2%7D-4000%28500%29%2B%5Cdfrac%7B0.4%28500%29%5E2%7D%7B2%7D%5D%5C%5C%5C%5C%3D%5B2200000-60500-2000000%2B50000%5D%5C%5C%5C%5C%3D189%2C500)
Hence, the additional cost incurred in dollars when production is increased from 500 units to 550 units = $ 189,500