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kodGreya [7K]
2 years ago
14

TRUE OR FALSE

Chemistry
1 answer:
lesantik [10]2 years ago
3 0
It depends on what unit/subject you're looking at.

Because in physics, I know that if you are considering Newton's theory of particles, all particles technically go in a straight line from the original direction. BUT, if you're looking at the Wave of the Particle theory, then you would assume that particles do not necessarily follow the above b/c they follow the properties of a wave... 
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A WATER WAY CONTAINS 10.3 MILIGRAMS OF IMPURITY PER GALLON OF WATER.HOW MANY MICROGRAMS OF IMPURITY ARE PRESENT PER LITER OF WAT
Trava [24]

I Gallon = 3.785 L 1 Mg = 1 mg gallon 3.785L. 3. The recommended adult dose of Elixophyllin®, a drug used to treat asthma, is 6.00 mg/kg of body mass. Calculate the dose in milligrams for a 112 lb person. (o oo Kg | K9 6.oong 112 15 = 3 04.7 - 3 2.20515 2.20516 my k.

Hope this answer will help you.

6 0
2 years ago
If 40.0 g of HCl react with an excess of magnesium metal, what is the theoretical yield of hydrogen?
lyudmila [28]

The balanced reaction is:<span>

Mg (s) + 2HCl (aq) --> MgCl 2 (aq) + H 2 (g) 

We are given the amount hydrochloric acid to be used for the reaction. This will be the starting point of the calculation.

40.0 g HCl ( 1 mol HCl / 36.46 g HCl) (1 mol H2 / 2 mol HCl) (2.02 g H2 / 1 mol H2) = 1.11 g H2</span>

8 0
3 years ago
A 1.00 g sample of n-hexane (C6H14) undergoes complete combustion with excess O2 in a bomb calorimeter. The temperature of the 1
Nadya [2.5K]

Answer:

-5,921x10⁶J/mol

Explanation:

Internal energy change (ΔU) for the reaction of combustion in the bomb calorimeter is:

ΔU = q calorimeter + q solution

Where:

q calorimeter is Ccal×ΔT (Ccal=4042J/°C) and (ΔT is 29,30°C-22,64°C=<em>6,66°C</em>)

q solution is c×m×ΔT (c= 4.184 J/g°C), (m=1502g H₂O), (ΔT is 29,30°C-22,64°C=<em>6,66°C</em>)

Replacing:

ΔU = 26920J + 41854J = <em>68774 J</em>

This energy is per g of n-hexane, now, per mole of n-hexane:

\frac{68774J}{1gHexane} *\frac{86,1g}{1mol}= -<em>5,921x10⁶J/mol</em>

<em>-negative because the energy is produced-</em>

I hope it helps!

5 0
3 years ago
Read 2 more answers
In a sample of UO 2, the uranium has been enriched so that 3.0% of it is 235U. How long could the fissioning of the uranium in t
8090 [49]

Explanation:

Molecular mass of UO_{2} is the sum of molecular mass of U and O_{2} molecule.

             Molar mass of UO_{2} = (238 + 32) g/mol

                                                                  = 270 g/mol

Hence, in 1 kg there are 1000 grams. So, total number of atoms given molecules present in 1 kg will be calculated as follows.

          \frac{1000 g}{270 g/mol} \times 6.023 \times 10^{23}atoms

                     = 2.229 \times 10^{24}

Hence, number of ^{235}U = \frac{3}{100} \times 2.229 \times 10^{24}

                                            = 6.69 \times 10^{22}

Now, let x seconds is required for burning 100 W lamp bulb. As 200 MeV is released per reaction.

             100 x =  6.69 \times 10^{22} \times 200 \times 10^{6} \times 1.6 \times 10^{-19}

                    x = 21.4 \times 10^{9} sec

Converting this value of x into years as follows.

                       x = \frac{21.4 \times 10^{9}}{3600 \times 24 \times 365}

                    x = 6.8 \times 10^{2} years

Thus, we can conclude that fissioning of the uranium in given situation requires 6.8 \times 10^{2} years to keep a 100 W lamp burning.

6 0
2 years ago
How many protons are there in a neutral, stable Hydrogen atom that makes up 99.985% of the element?
dem82 [27]
Answer is A because
3 0
3 years ago
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