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S_A_V [24]
3 years ago
13

Following a volcanic eruption which event is usualy the last one to be observed

Chemistry
2 answers:
Kay [80]3 years ago
8 0

Answer: usually the lava flowes out and starts burning down buildings and sturctures and by that happens people usually have evacutated the premises.

Explanation:

kvasek [131]3 years ago
6 0

Answer:

A. grasses begin to grow in soil with organic matter

B. tress begin to grow in thick rich soil

C. mosses begin to grow in thin rocky soil

D. lichens begin to cover bare rock

It would be B. because that comes last.

Explanation:

Whenever a volcano erupts, it puts a layer of rock over everything. Basically, over years and years, lichens will start growing and breaking down the rock. A bunch of years later, mosses will begin to grow in the "soil" that the lichens broke down. When the rocky dirt becomes actual dirt, grasses will start to grow. After that shrubs, and then trees.

Hope this helped! :)

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Here's what I get  

Explanation:

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4 0
3 years ago
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HELP! ASAP!
harina [27]

Given the model from the question,

  • The products are: N₂, H₂O and H₂
  • The reactants are: H₂ and NO
  • The limiting reactant is H₂
  • The balanced equation is: 3H₂ + 2NO —> N₂ + 2H₂O + H₂

<h3>Balanced equation </h3>

From the model given, we obtained the ffolowing

  • Red => Oxygen
  • Blue => Nitrogen
  • White => Hydrogen

Thus, we can write the balanced equation as follow:

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

  • Reactants: H₂ and NO
  • Product: N₂, H₂O and H₂

<h3>How to determine the limiting reactant</h3>

3H₂ + 2NO —> N₂ + 2H₂O + H₂

From the balanced equation above,

3 moles of H₂ reacted with 2 moles of NO.

Therefore,

5 moles of H₂ will react with = (5 × 2) / 3 = 3.33 moles of NO

From the calculation made above, we can see that only 3.33 moles of NO out of 4 moles given are required to react completely with 5 moles of H₂.

Thus, H₂ is the limiting reactant

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

8 0
2 years ago
Tomato juice has a pH of 4.20. Calculate the [H3O+] and [OH–] in tomato juice.
Free_Kalibri [48]
<span>[H3O+] = 10^(-pH) = 10^(-4.20) = 6.3 x 10^-5 M

pOH = 14 - pH = 14 - 4.20 = 9.80

[OH-] = 10^(-pOH) = 10^(-9.80) = 1.6 x 10^-10 M
</span>
8 0
3 years ago
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