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3 years ago

Which process represents a chemical change

2 answers:

8 0

A process that represents a chemical change is burning a piece of paper. I am not sure if this is a process but I hope this helps you!

Ganezh [65]3 years ago

4 0

Melting of ice could be one

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Help me with this???

Vikentia [17]

Yo sup??

Average velocity=total distance covered/total time taken

total distance covered=4 + 8=12 miles

total time taken=6 hours

Therefore

average velocity=12/6

=2 miles/hour

Hope this helps

8 0

3 years ago

Time shifting occurs when _______.

Svet_ta [14]

The answer is C, individuals copy works to view at a later time.

4 0

3 years ago

Read 2 more answers

A bat can detect small objects, such as an insect, whose size is approximately equal to one wavelength of the sound the bat make

blsea [12.9K]

Answer:

6.136 mm

Explanation:

given,

frequency emitted by the bat = 5.59 x 10⁴ Hz

speed of sound = 343 m/s

smallest insect bat can hear will be equal to the wavelength of the sound the bat make.

$\lambda = \dfrac{v}{f}$

$\lambda = \dfrac{343}{5.59\times 10^4}$

$\lambda = 6.136\times 10^{-3}}$

λ = 6.136 mm

so, the smallest size of insect that bat can hear is equal to 6.136 mm

8 0

3 years ago

Read 2 more answers

a ship A , steaming in a direction 030° with a steady 12 km/h, sight a ship B. The velocity of B relative to A is 10km/h in a di

pickupchik [31]

Answer: 11 km/h at 339° compass

Explanation:

A sees B moving south at 0 km/h

A is moving north at 12cos30 = 10.392 km/h

Therefore B must be moving north at 10.392 k/h

A is moving east at 12sin30 = 6 km/h

B appears to be moving west at 10 km/h

Therefore B must be moving west at 10 - 6 = 4 km/h

B is moving v = √(4² + 10.392²) = 11.135... 11 km/h

θ = arctan( -4 / 10.392) = -21.05 = 339°

8 0

3 years ago

A 46.0-kg box is being pushed a distance of 8.80 m across the floor by a force P whose magnitude is 171 N. The force P is parall

dolphi86 [110]

Answer:

a) 1504.8 J

b) 991.76 J

c) 0J

d) 0J

Explanation:

(a) The work done by the force P on the box is given by the following formula:

$W_P=Px$

P: applied force = 171N

x: distance in which the for P is applied = 8.80m

you replace the values of P and x and obtain:

$W_P=(171N)(8.80m)=1504.8J$

(b) The work don by the friction force is:

$W_f=F_fx=\mu N x=\mu Mg x$

μ = coefficient of kinetic friction = 0.250

M: mass of the box = 46.0kg

g: gravitational constant = 9.8 m/s^2

$W_f=(0.250)(46.0kg)(9.8m/s^2)(8.80m)=991.76J$

$N=Mg=(46.0kg)(9,8m/s^2)=450.8N$

but this force does not do work on the box because the direction is perpendicular to the direction of the force P.

$W_N=0J$

(d) the same as before:

$W_g=0J$

8 0

3 years ago