This item is solved through the concept of the conservation of momentum which states that the momentum before and after collision should be equal.
momentum = mass x velocity
(1,600 kg)(16 m/s) + (1.0x10^3 kg)(10 m/s) = (1600 + 1000 kg)(x)
The value of x is 13.69 m/s. Thus, their final speed is approximately letter D. 14 m/s.
Given:
The force of attraction is F = 48.1 N
The separation between the charges is
Also, the magnitude of charge q1 = q2 = q.
To find the magnitude of charge.
Explanation:
The magnitude of charge can be calculated by the formula
Here, k is the Coulomb's constant whose value is
On substituting the values, the magnitude of charge will be
Thus, the magnitude of each charge is 9.91 x 10^(-4) micro Coulombs.
Answer:
Energy is essentially work done by an object or on object.
From,
W = Fd
It's directly proportional to mass.
from,
K. E = 1/2mv²
Energy is directly proportional to mass.
P. E = mgh
Energy is directly proportional to mass.
H = mc∆T
Energy is directly proportional to mass.
Thus increasing mass will increase the energy also imparted on another object since all the above eqns show that relationship.
And for 2 moving bodies
K.Ei = K.Ef(energy conservation)
m1u²1 + m2u²2 = m1v²1 + m2v²2
The relationship is the same that the greater mass the greater the impact.
Explanation:
Given:
v₀ = 250 mph
v = 0 mph
t = 25 s
Find: a
v = at + v₀
(0 mph) = a (25 s) + (250 mph)
a = -10 mph/s
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