3 years ago

PLEASE HELP

Physics

2 answers:

Firlakuza [10]3 years ago

5 0

A bird flying near the mountain

siniylev [52]3 years ago

3 0

A person standing on the moon watching the earth rotate

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A baseball pitcher throws a baseball horizontally at a linear speed of 49.4 m/s. Before being caught, the baseball travels a hor

RideAnS [48]

Answer:

$v = 3.61 m/s$

Explanation:

As we know that ball travels horizontal distance of 24.7 m with uniform speed 49.4 m/s

so we will have

$t = \frac{x}{v_x}$

$t = \frac{24.7}{49.4}$

$t = 0.5 s$

now in the same time ball is turned by angle

$\theta = 52.7 rad$

now we know that

$\theta = \omega t$

$52.7 = \omega (0.5)$

$\omega = 105.4 rad/s$

now the tangential speed of a point at equator is given as

$v = r\omega$

$v = 0.0343(105.4)$

$v = 3.61 m/s$

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4 years ago

Using the black numbers on the stopwatch to answer the questions. What is the most accurate reading of seconds as indicated by t

jenyasd209 [6]

a. 5.3

should be your answer

hope I Helped!!!!

4 0

3 years ago

Two capacitors, a 15 micro F and a 25 micro F, are connected in parallel to a 60 Hz source. The total capacitive reactance is :_

Stells [14]

Answer:

Explanation:

The capacitive reactance is expressed as;

$X_c = \frac{1}{2 \pi fC}$

f is the frequency

C is the capacitance of the capacitor

Given

f = 60H

C = C1+C2 (parallel connection)

C = 15μF + 25μF

C = 40μF

C = $40 * 10^{-6}F$

Substitute into the formula:

$X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c = \frac{1}{0.0002512}\\X_c = 3,980.89$

<em>Hence the total capacitive reactance is 3980.89 ohms</em>

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3 years ago

Which of the following will produce the smallest ocean waves? WORTH 10 POINTS!

Mumz [18]

Answer: C. Weak winds that blow for short periods of time over small distances

Explanation:

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4 years ago

Una flecha tiene una rapidez de lanzamiento inicial de 18 m/s. Si debe dar en un blanco a 31 m de distancia, que está a la misma

maks197457 [2]

Answer:

34.8 and 55.2º

Explanation:

This is a projectile launching exercise, as we are told that the range of the arrow must be equal to its range and = 31 m let's use the equation

The scope equation is

R = v₀² sin 2θ /g

sin 2 θ = R g / v₀²

sin 2 θ = 31 9.8 / 18²

2 θ = sin⁻¹ 0.93765

θ = 34.8º

At the launch of projectiles we have two complementary angles with the same range in this case 34.8 and (90-34.8) = 55.2º

4 0

3 years ago