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ehidna [41]
4 years ago
7

One horsepower (hp) is the amount of power required to lift a 75-kg mass a vertical distance of 1 m in 1 s. What is 2 hp equival

ent to in watts (W)?
Physics
1 answer:
Vladimir [108]4 years ago
8 0

Answer:

1470 W

Explanation:

Power: This can be defined as the rate at which work is done or energy is used up. The S.I unit of power is Watt (W).

The expression for power is given as,

P = Energy/time

P = mgh/t ...................... Equation 1

Where P = power, m = mass, h = height, t = time, g = acceleration due to gravity.

Given: m = 75 kg, g =9.8 m/s², h = 1 m, t = 1 s.

Substitute into equation 1

P = (75×1×9.8)/1

P = 735 W.

From the above,

1 hp = 735 W

2 hp = (2×735) W

2 hp = 1470 W.

Hence 2 hp = 1470 W

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3. A bee flies forward at 4.9 for 33 s, lands on a flower and stays there for 7s, then flies back along its previous route at 1.
igor_vitrenko [27]

Answer:

None of these is correct.

Explanation:

The average speed can be derived from the sum of the total distance traveled and the total time taken.

 Total distance = 4.9 + 1.9  = 6.8

  Total time taken  = 33 + 39  = 72

So;

 Average speed  = \frac{total distance}{total time}  = \frac{6.8}{72}   = 0.014

None of the answer choices given is correct.

5 0
3 years ago
An object moves in a straight path. Its position x as a function of time t is presented by the equation x(t) = at – bt2+c, where
ankoles [38]

Answer:

The answer is below

Explanation:

Given that:

x(t) = at – bt2+c

a) x(t) = at – bt2+c

Substituting a = 1.4 m/s, b = 0.06 m/s2 and c =50 m gives:

x(t) = 1.4t - 0.06t² + 50

At t = 5, x(5) = 1.4(5) - 0.06(5)² + 50 = 55.5 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

v=\frac{x(5)-x(0)}{5-0}\\ \\v=\frac{55.5-50}{5-0}=1.1\\ \\v=1.1\ m/s

b) x(t) = 1.4t - 0.06t² + 50

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

v=\frac{x(10)-x(0)}{10-0}\\ \\v=\frac{58-50}{10-0}=0.8\\ \\v=0.8\ m/s

c) x(t) = 1.4t - 0.06t² + 50

At t = 15, x(5) = 1.4(15) - 0.06(15)² + 50 = 57.5 m

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

The average velocity (v) is given as:

v=\frac{x(15)-x(10)}{15-10}\\ \\v=\frac{57.5-58}{15-10}=0.1\\ \\v=0.1\ m/s

6 0
3 years ago
The point on the earth's surface directly above the point where the fault first ruptures is called the ____________.
Minchanka [31]
This point is called the epicenter. The epicenter is important when it comes to the Earth's surface, because it pinpoints where Earthquakes begin to take shape and occur. It is the place where the most damage is caused by an earthquake and is found above the hypocenter.
8 0
3 years ago
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Answer:

Its a parallel connection

Explanation:

The bulbs aren't in one line but two different parts, which makes it a parallel connection instead of a series connection.

7 0
4 years ago
Read 2 more answers
What is the acceleration of a car that travels in a straight line?
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hope this helps!! ✨
6 0
3 years ago
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