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Semmy [17]
2 years ago
10

Abcdefghijklmnopqrstuvwxyz

Physics
2 answers:
Natalka [10]2 years ago
8 0

Answer:

zyxwvutsrqponmlkjihgfedcba

Explanation:

emoclew rouy

AlladinOne [14]2 years ago
6 0

Answer:

lhgwljvqlivlajvliavpjavphvalhvqlhvqlhv

Explanation:

wlhfsougspuva???

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A 540 gram object is attached to a vertical spring, causing the spring’s length to change from 70 cm to 110 cm.
belka [17]

Answer:

Approximately 13\; {\rm N \cdot m^{-1}} (assuming that g = 9.81\; {\rm N \cdot kg^{-1}}.)

Explanation:

Let F_{\text{s}} denote the force that this spring exerts on the object. Let x denote the displacement of this spring from the equilibrium position.

By Hooke's Law, the spring constant k of this spring would ensure that F_\text{s} = -k\, x.

Note that the mass of the object attached to this spring is m = 540\; {\rm g} = 0.540\; {\rm kg}. Thus, the weight of this object would be m\, g = 0.540\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \approx 5.230\; {\rm N}.

Assuming that this object is not moving, the spring would need to exert an upward force of the same magnitude on the object. Thus, F_{\text{s}} = 5.230\; {\rm N}.

The spring in this question was stretched downward from its equilibrium by:

\begin{aligned} x &= (70\; {\rm cm} - 110\; {\rm cm}) \\ &= (-40)\; {\rm cm} \\ &= (-0.40) \; {\rm m}\end{aligned}.

(Note that x is negative since this displacement points downwards.)

Rearrange Hooke's Law to find k in terms of F_{\text{s}} and x:

\begin{aligned} k &= \frac{F_{\text{s}}}{-x} \\ &\approx \frac{5.230\; {\rm N}}{-(-0.40)\; {\rm m}} \\ &\approx 13\; {\rm N \cdot m^{-1}}\end{aligned}.

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2 years ago
Three forces of magnitude 10N, 5N and 4N act on an object in the directions North, West and East respectively. Find the magnitud
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That is a difference between a law and a hypothesis?
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<em>A hypothesis</em> is a limited explanation of a phenomenon; a scientific theory is an in-depth explanation of the observed phenomenon.

<em> A law</em> is a statement about an observed phenomenon or a unifying concept, according to Kennesaw State University. ... However, Newton's law doesn't explain what gravity is, or how it works.

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What is the force of friction between the dragsters tires and the track if the dragster mass is 300kg and the coefficient of the
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Ff=μN=μmg=0.8*300*10=2400 N

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