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3 years ago

Is FeN compound ironic or covalent? how do you know?

1 answer:

4 0

It is ionic (if that is what you meant). Fe (Iron) is a metal. N (Nitrogen) is a nonmetal. A nonmetal and a metal form a ionic bond. A nonmetal and a nonmetal forms a covalent bond.

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Nova, whose mass is 50kg drops 2 K, what is the amount of heat lost from Nova's body? (specific heat of the human body is 3470 J

Alex17521 [72]

Use the equation q=mc/\T, where q is the heat lost, m is mass, and /\T is the change in temperature, and c is the specific heat.
q=50kg(3470J/kg K)(2K)
q=<span>347000 J

Any other questions, just ask.
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6 0

4 years ago

Please answer the questions here in the attachment I attached below. They are all multiple choice.

Radda [10]

Answer:

abcbc

Explanation:

8 0

4 years ago

In a head-on collision, a ball of mass 0.3 kg travelling with velocity 2.8 m/s in the positive x-direction hits a stationary sec

Pie

Answer:

The final velocity of the first ball (0.3 kg) is 0.4 m/s in negative x direction.

Explanation:

Given;

mass of the first object, m₁ = 0.3 kg

initial velocity of the first ball, u₁ = 2.8 m/s

mass of the second ball, m₂ = 0.4 kg

initial velocity of the second ball, u₂ = 0

let the final velocity of the first ball, = v₁

let the final velocity of the second ball, = v₂

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.3 x 2.8) + (0.4 x 0) = 0.3v₁ + 0.4v₂

0.84 = 0.3v₁ + 0.4v₂

2.8 = v₁ + 1.333v₂ -------equation (1)

Apply one-direction velocity;

u₁ + v₁ = u₂ + v₂

2.8 + v₁ = 0 + v₂

v₂ = 2.8 + v₁

substitute the value of v₂ into equation (1)

2.8 = v₁ + 1.333v₂

2.8 = v₁ + 1.333(2.8 + v₁)

2.8 = v₁ + 3.732 + 1.333v₁

2.8 - 3.732 = v₁ + 1.333v₁

-0.932 = 2.333v₁

v₁ = -0.932 / 2.333

v₁ = -0.4 m/s

Therefore, the final velocity of the first ball (0.3 kg) is 0.4 m/s in negative x direction.

8 0

3 years ago

To subtract displacements, a ____________ needs to be set

andrezito [222]

I believe a vector needs to be set. but no 100% sure!
I hope this helps!

5 0

3 years ago

Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 4.50 m above

Virty [35]

$8.98×10^6\:\text{m}$

Explanation:

First we need to find the acceleration due to gravity on the planet. The wrench took 0.809 s to fall from a height of 4.50 m so we can use the equation

$y = -\frac{1}{2}gt^2$

Solving for g, we get

$g = -\dfrac{2y}{t^2} = -\dfrac{2(-4.50\:\text{m})}{(0.809\:\text{s})} = 13.8\:\text{m/s}^2$

Recall that the acceleration due to gravity on a planet's surface can be written as

$g = G\dfrac{M_p}{R_p^2}$

We can express the mass of the planet $M_p$ in terms of its density $\rho$ as follows:

$M_p = \rho \left(\dfrac{4\pi}{3}R_p^3\right) = \dfrac{4\pi}{3}\rho R_p^3$

The expression for g then becomes

$g = \dfrac{G}{R_p^2} \left(\dfrac{4\pi}{3}\rho R_p^3\right) = \dfrac{4\pi G}{3}\rho R_p$

Solving for $R_p,$ we get

$R_p = \dfrac{3g}{4\pi G\rho}$

$\:\:\:\:\:\:\:= \left[\dfrac{3(13.8\:\text{m/s}^2)}{4\pi (6.674×10^{-11}\:\text{Nm}^2\text{/kg}^2)(5500\:\text{kg/m}^3)}\right]$

$\:\:\:\:\:\:\:= 8.98×10^6\:\text{m}$

3 0

3 years ago