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o-na [289]
3 years ago
8

the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equ

ator option d increase from pole to equator which is the answer​
Physics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

D. Increases from pole to equator

Explanation:

I majored in Science

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How do you know whether to put a nine or a 10 in front of the number on the weather station
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If the air pressure on the station model is 500 or more, place a 9 in front of this number. If the pressure number on the station is less than 500 add a 10 in front of this number. 

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A wavelength is a measure of distance between two consecutive crests or trough. So , the unit of wavelength is same as unit of distance. I.e metre

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Which of the following are simple machines?<br> Select all that apply.
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A Boulder drops in the water and creates a wave with a period of 2s/cycle and a wavelength of .75 m/cycle. How fast is the wave
laiz [17]

Answer:

v = 0.375 m/s

Explanation:

Given that,

The wavelength of a wave is 0.75 m/cycle

The period of a wave is 2s/cycle

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v=\dfrac{d}{t}

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v=\dfrac{0.75}{2}\\\\v=0.375\ m/s

So, the speed of the wave is equal to 0.375 m/s.

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3 years ago
A que profundidad esta nadando una persona dentro de una alberca si la presión absoluta sobre ésta es de 156kPa?
lara31 [8.8K]

Answer:

La persona está nadando en la alberca a una profundida de 5.575 metros.

Explanation:

La presión absoluta (P_{tot}) experimentada por la persona es la suma de la presión atmosférica (P_{atm}) y la presión hidrostática de la columna de agua de la alberca (P_{h}), medidas en kilopascales. Es decir,

P_{tot} = P_{atm}+P_{h} (1)

P_{tot} = P_{atm} + \frac{\rho\cdot g \cdot z}{1000} (2)

Donde:

\rho - Densidad del fluido de la alberca, medida en kilogramos por metro cúbico.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

z - Profundidad de la persona en la alberca, medida en metros.

Si sabemos que P_{atm} = 101.325\,kPa, \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} y P_{tot} = 156\,kPa, entonces la profundidad de la persona en la alberca es:

156 = 101.325 +\frac{(1000)\cdot (9.807)\cdot z}{1000}

54.675 = 9.807\cdot z

z = 5.575\,m

La persona está nadando en la alberca a una profundida de 5.575 metros.

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3 years ago
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