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Burka [1]
3 years ago
6

Cd is congruent to df, e bisects df and cd= 14.2. find ef.

Mathematics
2 answers:
svetlana [45]3 years ago
8 0
7.1 is the value of Ef where cd=df
Tom [10]3 years ago
4 0

Answer:

7.1 units.

Step-by-step explanation:

It is given that cd is congruent to df, e bisects df and cd= 14.2.

We have to find the measure of ef.

Using given information we get

cd\cong df

cd=df=14.2             (Measure of congruent segments are equal)  ... (1)

de=ef=\dfrac{df}{2}   (e bisects df)      ... (2)

Using (1) and (2) we get

ef=\dfrac{14.2}{2}

ef=7.1

Hence, the measure of ef is 7.1 units.

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Which list of numbers could be used to name each point plotted on the number line?
elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

numbers are {3.46,3.47,3.48,3.49,3.50,3.51,3.52,3.53,3.54,3.55,3.56,3.57,3.58,3.59}

5 0
2 years ago
What conclusions can you draw by comparing the mean and MAD repairs per vehicle for each type of Vehicle
trasher [3.6K]
The mean would tell you the average number of repairs per vehicle type. It is the total amount of repairs divided by the total number of vehicles.

The mean absolute deviation (MAD) describes how close the values are typically to the mean. It is an average of the distances the individual points are from the mean. Basically, it tells how spread out the data is.
5 0
3 years ago
Consider the expression 625(5xy)^-3/ (5x)^2 y^7
andre [41]
<span>625(5xy)^-3/ (5x)^2 y^7
     
             625 
= --------------------   /  25x^2y^7
      125 x^3y^3

= 5/x^3y^3    / </span>25x^2y^7
= 5/x^3y^3   *  (1/ 25x^2y^7)
= 1 / 5x^5y^10

answer


         1
-----------------
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3 0
3 years ago
Triangle ABC is similar to triangle PQR, as shown below:
natita [175]

Answer:

\frac{q}{b}=\frac{r}{c}

Step-by-step explanation:

Consider the options for this question are as follow,

  • \frac{q}{c}=\frac{r}{b}
  • \frac{c}{p}=\frac{b}{a}
  • \frac{c}{a}=\frac{q}{r}
  • \frac{q}{b}=\frac{r}{c}

Here, In triangles ABC and PQR,

AB = c, BC = a, AC = b, PQ = r, QR = p and PR = q,

Since,

\traingle ABC\sim \triangle PQR

We know that,

The corresponding sides of similar triangles are in same proportion,

Thus,

\frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}

\frac{c}{r}=\frac{a}{p}=\frac{b}{q}

\frac{r}{c}=\frac{p}{a}=\frac{q}{b}

\implies \frac{q}{b}=\frac{r}{c}

3 0
3 years ago
Read 2 more answers
I PROMISE I WILL LET EVERYBODY KNOW WHAT GRADE I GET WHEN I KNOW
makkiz [27]

Answer:

are those 3 different question of just one?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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