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umka2103 [35]
3 years ago
13

John's dog eats 8 ounces of dog food each day. John bought 20-pound bag of dog food. How many 8 - ounces are in 28- pounds of do

g food?
Mathematics
2 answers:
aleksley [76]3 years ago
5 0
8x3= 24...
there are 3 8 ounces in 28 pounds of dog food...
hope this helps!! HAGD!
nignag [31]3 years ago
4 0
There are 448 ounces in 28 pounds of dog food. Divide 448 by 8 to find out how many 8 ounces there are. There are 56 8 ounces in 28 pounds of dog food.
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Write a quadratic function whose zeros are -12 and -2.
AnnZ [28]

Answer:

(x+12) (x+2)

x(x+12)+2(x+12)

x^2+12x+2x+24

x^2+14x+24

Step-by-step explanation:

7 0
2 years ago
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Help me iv been trying from this morning
GalinKa [24]

Answer:

i did the first

Step-by-step explanation:

1st way

Standard form: a(X-h)²+k = ( -2/3X² -16/3X -32/3) +32/3 -17/3 = -2/3(X +4)² +5

y = -2/3*X^2-16/3*X-17/3

X = -4 ±√( 15/2) = -6.7386, or -1.2614

Axis of symmetry: X= -4; Vertex (maximum)=(h,k)=( -4, 5); y-intercept is (0,-5.66666666667)

two real roots: X=-1.2613872124776866 and -6.738612787477313

5 0
3 years ago
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jenny receives total employee benefits that are 24.5% of her gorss annual pay.if jenny has a gross annual pay of 70,000 how much
patriot [66]
You can change 24.5% by moving the decimal point
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4 0
3 years ago
(AP Calc) the graph of the function f shown above has three line segments....
I am Lyosha [343]

Answer:

B

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 1, 6 ] and from the graph

f(b) = f(6) = 0

f(a) = f(- 1) = 0, thus

average rate of change = \frac{0-0}{6+1} = \frac{0}{7} = 0

7 0
3 years ago
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ale4655 [162]

Answer:

Area = 58 \ units^2

Step-by-step explanation:

We can start by finding the third side of the triangle/the side of the square using the Pythagorean Theorem:

a^2+b^2=c^2

In this case the side length of the square would be represented by the variable "c" as it is the hypotenuse:

3^2+7^2=c^2

9+49=c^2

c^2=58

c=\sqrt{58}

Since the area of a square is the side length square then...

Area =( \sqrt{58} )^2

The square root and the squared cancel out giving us...

Area = 58 \ units^2

3 0
3 years ago
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