Answer: X = kuv/ (u+v)
that means that x(u+v)/(uv) = k, a constant. so you want x such that,
x(3+3)/(3*3) = 3(3+1)/(3*1)
x=6
To determine the answer of Part A draw the equilateral triangle and the to determine the coordinates of of the third charge use that triangle.
To calculate the gravitational field strength in part B from each of the charges use the following equation.
E=kcq/r2
If you would add those values then you can use the symmetry about the y axis to make the vector addition a litter easier.<span />
Answer:
Acute angle, doesn't have a 90 degree angle to be a right triangle, neither a wide angle to be an obtuse triangle.
Answer:
670
Step-by-step explanation:
2003-814=1189
1189-519=670
X - 4 +6 -x
x - x = -2
0 = -2
No solution
