Answer:
1) d. all of the above
2) a. cut from a barbed wire at a dairy farm
3) check 3, 4, 5
4) b. suburban areas
5) true
6) is true
7) d. "but..."
8) true
9) check 1, 2, 5
10) a. animal bites
11) c. smallpox
12. antibodies
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Explanation:
Sometimes, a solution contains more dissolved solute than is normally possible. This type of solution is said to be supersaturated. A saturated solution can become supersaturated if more solute is added while the temperature is raised.
hope it will help u ✌️
Answer:
1.59 M
Explanation:
<em>What is the concentration (M) of CH₃OH a solution prepared by dissolving 11.7 g of CH₃OH sufficient water to give exactly 230 mL of solution?</em>
Step 1: Given data
- Volume of solution: 230 mL (0.230 L)
Step 2: Calculate the moles corresponding to 11.7 g of CH₃OH
The molar mass of CH₃OH is 32.04 g/mol.
11.7 g × 1 mol/32.04 g = 0.365 mol
Step 3: Calculate the molarity of the solution
M = moles of solute / liters of solution
M = 0.365 mol / 0.230 L = 1.59 M
The weight/weight percent(%w/w) of NaCl in solution : 33.03%
<h3>Further explanation</h3>
Given
Mole fraction of NaCl : 0.132
Required
The weight/weight percent of NaCl
Solution
1 mol solution : 0.132 mol NaCl + 0.868 mol H₂O
mass NaCl :
mass H₂O :
Total mass = 7.714 + 15.64 = 23.354 g