The yield of aluminium obtained from 1 m^3 of bauxite is 419810 g
<h3>What is a Percent yield</h3>
A percent yield of a substance measures the amount of the substance actually obtained as a percentage ratio of expected yield.
Percent yield = actual yield / expected yield × 100%
<h3>How to calculate the mass of aluminium obtained from bauxite </h3>
From the data given:
40 % of the bauxite is converted to aluminium oxide.
Volume of bauxite = 1 m^3
40 % of 1 m^3 = 0.4 m^3
volume of aluminium oxide = 0.4 m^3
density of aluminium oxide = 3965 kg/m^3
- Using mass = density × volume
mass of aluminium oxide = 0.4 × 3965 kg
mass of aluminium oxide = 1586 kg
Formula of aluminium oxide is Al203
molar mass of aluminium oxide = 102 g
- percentage mass of aluminium in one mole of aluminium oxide = mass of aluminium / mass of aluminium oxide × 100 %
Percentage mass of aluminium in aluminium oxide = 54/102 × 100
Percentage mass of aluminium in aluminium oxide = 52.94 %
Expected mass of aluminium from aluminium oxide = 52.94 × 1586
Expected mass of aluminium = 839.62 kg
Actual yield = 40 % × 839.62
Actual yield of aluminium = 419.81 kg
mass of aluminium in grams = 419810 g
Therefore, mass of aluminium obtained from 1 m^3 of bauxite is 419810 g
Learn more about percent yield at: brainly.com/question/8638404
