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Stels [109]
3 years ago
5

Given the unbalanced equation: ___Al2(SO4)3+___Ca(OH)2—>___Al(OH)3+__CaSO4

Chemistry
1 answer:
nasty-shy [4]3 years ago
8 0

Answer:

The answer to your question is letter B. 9

Explanation:

Unbalanced reaction

                     Al₂(SO₄)₃  +  Ca(OH)₂   ⇒    Al(OH)₃   +   CaSO₄

                     Reactants             Elements      Products

                          2                          Al                     1

                          3                           S                     1

                         14                           O                    7

                          1                           Ca                    1

                          2                           H                     3

Balanced reaction

                    Al₂(SO₄)₃  + 3Ca(OH)₂   ⇒   2Al(OH)₃   +   3CaSO₄

                     Reactants             Elements      Products

                          2                          Al                    2

                          3                           S                    3

                         18                           O                  18

                          3                           Ca                  3

                          6                            H                    6

The sum of the coefficients is 1 + 3+ 2+ 3 = 9

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Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.
goblinko [34]

Answer:

Vapour pressure of cyclohexane at 50°C is 490torr

Vapour pressure of benzene at 50°C is 90torr

Explanation:

Using Raoult's law, pressure of a solution is defined by the sum of the product sbetween mole fraction of both solvents and pressure of pure solvents.

P_{solution} = X_{A}P^0_{A}+X_{B}P^0_{B}

In the first solution:

X_{cyclohexane}=\frac{2.5mol}{2.5mol+1.5mol} =0.625

X_{benzene}=\frac{1.5mol}{2.5mol+1.5mol} =0.375

340torr = 0.625P^0_{A}+0.375P^0_{B} <em>(1)</em>

For the second equation:

X_{cyclohexane}=\frac{3.5mol}{3.5mol+1.5mol} =0.700

X_{benzene}=\frac{1.5mol}{3.5mol+1.5mol} =0.300

370torr = 0.700P^0_{A}+0.300P^0_{B}<em>(2)</em>

Replacing (2) in (1):

340torr = 0.625P^0_{A}+0.375(1233.3-2.333P^0_{A})

340torr = 0.625P^0_{A}+462.5-0.875P^0_{A}

-122.5torr = -0.250P°A

P^0_{A} = 490 torr

<em>Vapour pressure of cyclohexane at 50°C is 490torr</em>

And for benzene:

370torr = 0.700*490torr+0.300P^0_{B}

P^0_{B}=90torr

<em>Vapour pressure of benzene at 50°C is 90torr</em>

3 0
3 years ago
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torisob [31]

Decrease

Increase  

Increase

Decrease

Increase

Decrease

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4 0
3 years ago
4. How many milligrams are in 5.25 x 10-13 kg?<br><br> the “-13” is an exponent
rusak2 [61]

5. 25 x 10⁻⁷mg

Explanation:

This is mass conversion from mg to kg;

The kg is a quantity of mass used to measure the amount of matter in a substance.

   Given mass = 5.25 x 10⁻¹³kg

The kilo-  is a prefix that denotes 10³

  therefore;

         1000g = 1kilogram

 the milli-  is a prefix that denotes 10⁻⁻³

       1000mg = 1g

Now that we know this, we can convert:

   5.25 x 10⁻¹³kg  x \frac{1000g}{1kg}  x \frac{1000mg}{1g}   =  5. 25 x 10⁻¹³ x 10⁶mg

      =  5. 25 x 10⁻⁷mg

learn more:

Conversion brainly.com/question/1548911

#learnwithBrainly

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In a salt solution, what happens to sodium and chloride ions?
iVinArrow [24]
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