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4 years ago

Which object has the greatest inertia?

2 answers:

6 0

The greatest amount of inertia can be calculated by the following equation

Kinetic Energy = 0.5 x mass x (velocity)^2

You are trying to find Kinetic Energy.

KE = 0.5 x 30kg x 100

KE = 1,500

Your answer is (2) because when using the equation, the child has the greatest amount of inertia.

Talja [164]4 years ago

3 0

I believe 4
but im really not sure

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A 9.76-m ladder with a mass of 22.6 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upw

galben [10]

Answer:

Part a)

$\tau_{net} = 1397.1 Nm$

Part b)

$I = 702.06 kg m^2$

Explanation:

Part a)

Torque on the rod is due to two forces

(i) Due to weight of the rod at mid point

(ii) Due to external force applied at the end

Now we have

$\tau_{net} = FL - mg\frac{L}{2}$

$\tau_{net} = 254(9.76) - (22.6)(9.81)(\frac{9.76}{2})$

$\tau_{net} = 1397.1 Nm$

Part b)

As per Newton's law we know that

$\tau = I\alpha$

now we have

$1397.1 Nm = I(1.99 rad/s^2)$

$I = 702.06 kg m^2$

6 0

3 years ago

Earth, one of eight planets, resides in the spiral galaxy the Milky Way, which is one of the estimated billions of galaxies in s

liberstina [14]

Answer:

One of Eight Planets : Earth

Spiral galaxy, One of the estimated billions of galaxies: Milky Way

Galaxy: Milky Way

Explanation:

According to the definition, appositive or apposition is a grammatical construction which represents similar noun phrases and nouns where one serves or defines the other one.

Here, the ultimate examples of apposition are mentioned in the given statement as Earth: One of Eight Planets, Milky Way: Spiral Galaxy and one of the estimated billions of galaxies: Milky Way.

With such kinds of words, it's easier to understand the noun or renames with a short definition written as a phrase.

6 0

3 years ago

What is an automatic stabilizer?

Oduvanchick [21]

Answer:

c. It refers to any government program that tends to reduce fluctuations in GDP automatically.

Explanation:

Automatic Stabilizer is nothing but any scheme or program that that tends to reduce fluctuations in GDP automatically. It is generally intended to stabilize the GDP of a nation.

For examples In cases of economic slow down, the government sells its ownership in public sectors undertakings like, railways, oil and natural gases, to private players. So, that government has some money to combat the slowdown.

3 0

4 years ago

A man cleaning his apartment pushes a vacuum cleaner with a force of magnitude 84.5 N. The force makes an angle of 33.9 ◦ with t

Sav [38]

Answer:

183.75641 Joules

Explanation:

F = Force of the vacuum cleaner = 84.5 N

s = Displacement of the vacuum cleaner = 2.62 m

$\theta$ = Angle the force makes with the horizontal = 33.9°

Work done is given by

$W=F\times scos\theta\\\Rightarrow W=84.5\times 2.62\times cos33.9\\\Rightarrow W=183.75641\ J$

The work done by the force of the vacuum cleaner is 183.75641 Joules

6 0

3 years ago

How much work is done if you push a 200 N box across a floor with a force of 50 N for a distance of 20m

vovikov84 [41]

<h2>Answer: 1000 J</h2>

The Work $W$ done by a Force $F$ refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.

It should be noted that it is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:

$1J=(1N)(1m)=Nm$

Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:

$W=(F)(d)$ (1)

When they are not parallel, both directions form an angle, let's call it $\alpha$ . In that case the expression to calculate the Work is:

$W=Fdcos{\alpha}$ (2)

For example, in order to push the 200 N box across the floor, you have to apply a force along the distance $d$ to overcome the resistance of the weight of the box (its 200 N).

In this case both <u>(the force and the distance in the path) are parallel</u>, so the work $W$ performed is the product of the force exerted to push the box $F=50N$ by the distance traveled $d$ . as shown in equation (1).

Hence:

$W=(50N)(20m)$

$W=1000Nm=1000J$ >>>>This is the work

8 0

3 years ago