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Dennis_Churaev [7]

3 years ago

12

PLEASE HELP!!!

1 answer:

Simora [160]3 years ago

8 0

I only know what number 1. is and its Mechanical Energy.

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Consider the third period of the periodic table. Which element has the smallest atomic radius?

Anettt [7]

According to periodic trends in the periodic table, the atomic radius decreases from left to right.

In period three, the element with the smallest atomic radius would be the element in the rightmost area. Protons increase as it goes to the right, which would mean they pull in electrons closer which decreases the size.

So in period 3, the element with the smallest atomic radius is Argon (Ar).

3 0

4 years ago

3. A car is traveling up a 3% grade, with the speed of 85mph, on a road that has good, wet pavement. A deer jumps out onto the r

solniwko [45]

Answer:

Explanation:

From the given information;

Let assume that:

the wheel radius = 15 inches

the driveline slippage = 3%; &

the gear reduction ratio (overall) = 2.5 to 1

So; using the equation:

$v_1= \dfrac{2 \pi r n_o (1 -i)}{\varepsilon_o}$

$v_1= \dfrac{2 \times 3.14 \times \dfrac{15}{12} \times \dfrac{85}{100} (1 -0.03)}{2.5}$

$v_1= \dfrac{2 \times 3.14 \times \dfrac{15}{12} \times \dfrac{85}{100} (0.97)}{2.5}$

$v_1 = 126.92 \ fp^3$

$frl = 0.01 ( 1+ \dfrac{v}{147}) \ if \ v \ is \ ft/sec$

$frl = 0.01 \Bigg( 1+ \dfrac{\dfrac{126.92 +(20)1.47 }{2} }{147}\Bigg)$

$S = \dfrac{v_b ( v_1^r-v_2^r)}{2g(n_b \mu + frl \pm sin \ y}$

where;

$\mu = 0.6$

$291 = \dfrac{1.64( 126.92^2-29.9^2)}{64.4(n_b \times 0.6 +0.01532 +0.03}$

$n_b = 1.33 \to which \ is \ not \ possible$

However;

$n_b \mu = 1.33(0.6) = 0.80$

$\mu = 0.9 \to$ if the car's anti-clock breaking system did not fail

Thus;

$n_b (0.9) = 0.80$

$n_b =\dfrac{ 0.80}{(0.9) }$

$n_b = 0.89$

Hence, the distance is possible if the anti-clock breaking system did not fail.

4 0

3 years ago

How long does it take a car to travel 450 km at 75 km/hr

Mashutka [201]

Answer:

06:00:00

Explanation:

5 0

3 years ago

Read 2 more answers

What would the acceleration of a car be from a stoplight if it started at 0 m/s and reached a

trapecia [35]

Answer:

The acceleration of a car would be: $a=12.8$ m/s²

Explanation:

Given

Initial velocity = $v_1=0$ m/s

Final velocity = $v_f=100$ m/s

Time elapsed = $t = 7.8$ s

To determine

We need to determine the acceleration of a car.

We know that acceleration is basically the rate of change in velocity over time.

Thus,

We can determine the acceleration using the formula

$\:\:\:a=\:\frac{v_f-v_i}{t}$

where

$a$ is the acceleration

$v_1$ is the initial velocity

$v_f$ is the final velocity

$t$ is time elapsed

now substituting the values $v_1=0$ , $v_f=100$ , and $t = 7.8$ in the formula

$\:\:\:a=\:\frac{v_f-v_i}{t}$

$a=\:\frac{100-0}{7.8}$

$a=\frac{100}{7.8}$

$a=12.8$ m/s²

Therefore, the acceleration of a car would be: $a=12.8$ m/s²

3 0

3 years ago

2. What is the percent composition of sulfur in H2SO4?

allochka39001 [22]

Answer:

C. 32.7%

Explanation:

% composition = ( mass S / mass H2SO4 ) × 100 = 32.08/ 98.10 × 100 = 32.7 % pls mark brainliest

6 0

3 years ago