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kenny6666 [7]
4 years ago
8

The true brightness of an object is called its

Physics
2 answers:
g100num [7]4 years ago
8 0
<span>The true brightness of an object is called its luminosity. It is the total amount of energy emitted by bright or meteorological objects over a period of time. It has the SI unit of joules per second or watts. So the answer is letter A. Intensity is the measure of how strong the substance or object is when it projects something. Magnitude is a measure of how great is the size the object produces. Viscosity is the measure of flow of a substance.</span>
schepotkina [342]4 years ago
7 0

The answer is A.luminosity

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9) If a wave has a speed of 362 m/s and a period of 4.17 s, what is its wavelength?
kakasveta [241]

Answer:

Option B (1.51 m)

Explanation:

U 2 can help me by marking as brainliest........

5 0
2 years ago
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At a particular instant, a hot air balloon is 100 m in the air and descending at a constant speed of 2.0 m/s. at this exact inst
rewona [7]

Answer:

86.4 m  horizontal from landing spot

Explanation:

Find out how long before the ball hits the ground

 vertical speed  of ball = -2  m/s     gravity = - 9.81 m/s^2

find time to hit ground from 100 m  

          ( height will be<u> zero</u> when it hits the ground)

<u>0 </u>=  100  - 2 t  - 1/2 ( 9.81) t^2

        use Quadratic Formula to find t = 4.32 seconds

              horizontal speed of ball = 20 m/s  

in 4.32 seconds it will travel horizontally   20  m/s * 4.32 s = 86.4 m

3 0
2 years ago
Suppose you could fit 100 dimes, end to end, between your card with the pinhole and your dime-sized sunball. how many suns could
Naddika [18.5K]

Answer: 100 suns

Explanation:

We can solve this with the following relation:

\frac{d}{x_{sunball-pinhole}}=\frac{D}{x_{sun-pinhole}}

Where:

d=17.91 mm =17.91(10)^{-3}  m is the diameter of a dime

D is the diameter of the Sun

x_{sun-pinhole}=150,000,000 km=1.5(10)^{11}  m is the distance between the Sun and the pinhole

x_{sunball-pinhole}=100 d=1.791 m is the amount of dimes that fit in a distance between the sunball and the pinhole

Finding D:

D=\frac{d}{x_{sunball-pinhole}}x_{sun-pinhole}

D=\frac{17.91(10)^{-3}  m}{1.791 m} 1.5(10)^{11}  m

D=1.5(10)^{9}  m This is roughly the diameter of the Sun

Now, the distance between the Earth and the Sun is one astronomical unit (1 AU), which is equal to:

1 AU=149,597,870,700 m

So, we have to divide this distance between D in order to find how many suns could it fit in this distance:

\frac{149,597,870,700 m}{1.5(10)^{9}  m}=99.73 suns \approx 100 suns

8 0
3 years ago
PART A:
olga55 [171]

Answer:

4 m/s^{2}

Explanation:

From Equilibrium of forces, The Tension in string is cancelled by the Weight (product of mass and acceleration due to gravity) of the body acting downwards.

The Net force = Mass * Acceleration.

Since Net Force = 20 Newton, Mass = 5kg, therefore;

20 = 5kg * acceleration. Dividing the RHS and LHS of the equation by 5, we have;

Acceleration = \frac{20}{5} which gives 4.

Note: RHS means Right Hand Side.

         LHS means Left Hand Side.

 

7 0
3 years ago
4. The flow of electric charge is know as
vredina [299]

Answer:

electrons

Explanation:

An electric current is said to exist when there is a net flow of electric charge through a region. In electric circuits this charge is often carried by electrons moving through a wire. It can also be carried by ions in an electrolyte, or by both ions and electrons such as in an ionized gas (plasma).

5 0
3 years ago
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