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Oduvanchick [21]
3 years ago
9

All objects in the universe are attracted to each other by the force of. A. effort

Physics
2 answers:
dybincka [34]3 years ago
6 0

Answer:

So, I noticed that somebody rated the other answer here 1 star. But, if you really can't get it, (which doesn't make sense because the answer is literally in it) the answer is gravity. Which would make the answer D. gravity

Explanation:

stepladder [879]3 years ago
4 0

Answer:

It encapsulates the idea that all the particles of matter in the universe attract each other through the force of gravity – Newton's law tells us how strong that attraction is. ...

Explanation:

your answer

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Akia is balancing the equation Na + H2O NaOH + H2. He tries to find the coefficients that will balance the equation. How could h
bixtya [17]

Answer:

by counting each individual atom and making sure the number of each kind of atom is the same in the reactants and the products. - This is the answer.

Explanation:

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3 years ago
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What is the mass of an atom with six protons, seven neutrons, and eight electrons?
qaws [65]

Answer:

13

Explanation:

The mass of an atom= number of protons + number of neutrons

7 0
3 years ago
You are given a sample of metal and asked to determine its specific heat. You weight the sample and find that its weight is 28.4
lidiya [134]

Answer:

The samples specific heat is 14.8 J/kg.K

Explanation:

Given that,

Weight = 28.4 N

Suppose, heat energy E=1.25\times10^{4}\ J

Temperature = 18°C

We need to calculate the samples specific heat

Using formula of specific heat

Q=mc\Delta T

c=\dfrac{Q}{m\Delta T}

Where, m = mass

c = specific heat

\Delta T = temperature

Q = heat

Put the value into the formula

c=\dfrac{1.25\times10^{4}}{\dfrac{28.4}{9.8}\times(18+273)}

c=14.8\ J/kg. K

Hence, The samples specific heat is 14.8 J/kg.K

8 0
3 years ago
What is potential energy​
JulsSmile [24]

Answer:

An Energy held by an object because of its position relative by other objects

Explanation:

6 0
4 years ago
A 15.0 kg crate, initially at rest, slides down a ramp 2.0 m long and inclined at an angle of 20.0° with the horizontal. Using t
Elis [28]

The component of the crate's weight that is parallel to the ramp is the only force that acts in the direction of the crate's displacement. This component has a magnitude of

<em>F</em> = <em>mg</em> sin(20.0°) = (15.0 kg) (9.81 m/s^2) sin(20.0°) ≈ 50.3 N

Then the work done by this force on the crate as it slides down the ramp is

<em>W</em> = <em>F d</em> = (50.3 N) (2.0 m) ≈ 101 J

The work-energy theorem says that the total work done on the crate is equal to the change in its kinetic energy. Since it starts at rest, its initial kinetic energy is 0, so

<em>W</em> = <em>K</em> = 1/2 <em>mv</em> ^2

Solve for <em>v</em> :

<em>v</em> = √(2<em>W</em>/<em>m</em>) = √(2 (101 J) / (2.0 m)) ≈ 10.0 m/s

3 0
3 years ago
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