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Liono4ka [1.6K]
2 years ago
8

3(2y-4) - 2 ) = 0.4 (1+y)

Mathematics
1 answer:
Lelu [443]2 years ago
3 0
6y-12-2=0.4+0.4y
6y-10-0.4=0.4-0.4+0.4y
6y-6y-9.6=0.4y-6y
(-9.6=-5.6y)/5.6
1.7143=y
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328,268.16

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The width of a rectangle is the sum of the length and 1. The area of the rectangle is 20 units. What is the width, in units, of
IRISSAK [1]

Answer:

W=5

Step-by-step explanation:

W=Width=Length + 1

L = Length

Area = Length * Width = 20

Area = L * W = L * (L+1) = 20

Distribute the L:   L^2 + L = 20

Subtract 20 from both sides: L^2 + L -20 = 20-20

Simplify:  L^2+L-20=0

Factor (L-4)(L+5)=0

Solve using the zero property: L-4=0, L=4      L+5=0, L=-5

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6 0
3 years ago
A square has side length (x+5) units. What is it’s area
daser333 [38]

The area of square is x^{2}+10 x+25 square units

<h3><u>Solution:</u></h3>

Given that square has side length (x+5) units

To find: area of square

<em><u>The area of square is given as:</u></em>

\text {Area of square }=\mathrm{a}^{2}

Where "a" is the length of side

From question, length of each side "a" = x + 5 units

Substituting the value in above formula,

\text {Area of square }=(x+5)^{2}

{\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}

\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}

Thus the area of square is x^{2}+10 x+25 square units

7 0
3 years ago
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