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strojnjashka [21]
3 years ago
15

Joe borrowed $2,000 from the bank at a rate of 7% simple interest per year. How much interest did he pay in 8 years?

Mathematics
2 answers:
Artist 52 [7]3 years ago
7 0

Answer:

$1120

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just don’t want to waste my time in case you don’t want me to :)

storchak [24]3 years ago
6 0

Answer:

Do 2000 x 8

Step-by-step explanation:

16,0000

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Each morning librarians place 560 books on a book shelf in the school library. Each student that visits library that day takes e
Alex73 [517]

Answer:

Step-by-step explanation:

560=3s+b

b.

560=3×150+b

b=560-450=110

when s=149,b=560-3×149=560-447=113

s=2,b=560-3×2=560-6=554

s=1,b=560-3×1=557

s=0,b=560-3×o=560

so domain of b={110,113,116,...,554,557,560}

7 0
3 years ago
What's the equation of this line ?
Gennadij [26K]
Y = -3x + 7

good luck!
5 0
3 years ago
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Solve x show your work​
Bezzdna [24]

Answer:

55+x+74+54= 180 degree ( being the sum of all angle of the triangle )

or, 183 +x = 180degree

or, x=(180-183)degree

or, x= -3degree ans

4 0
3 years ago
What is 10500 m = ..... km?
Vinvika [58]
Since there are 100p meters in a kilometer you divide 10500 by 1000 and you get 10.5 km
8 0
3 years ago
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An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
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