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Elden [556K]
3 years ago
6

How many milligrams of a 20mg sample of cesium-137 remain after 60 years

Chemistry
1 answer:
andrey2020 [161]3 years ago
5 0
Cs -137 has a half life of about 30 years. If 60 years pass, there is two half lives passed so 1/2 * 1/2= 1/4. Take 1/4 and multiply it with the mass given:
(1/4)*20mg=5mg left
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analyze why is the result of the stage of meiosis shown below an advantage for organisms that reproduce sexually.
patriot [66]

Answer:

Meiosis produces haploid cells (gametes), which contain single chromosomes, or on-half the number of chromosomes in diploid cells. When a sperm and an egg join, the single chromosomes pair up, which results in genetic diversity in the offspring

6 0
2 years ago
Is alka seltzer and acid or a base or netural
fiasKO [112]

Answer:

Base

Explanation:

Why is Alka-Seltzer a base?

Alka-Seltzer contains sodium bicarbonate and citric acid. The sodium citrate acts as an antacid. Excess sodium bicarbonate from the Alka-Seltzer acts to neutralize base.

5 0
2 years ago
A chemical reaction in which one element replaces another element in a compound can be catergorized as a
Gwar [14]

Answer:

\huge\boxed{\sf Single \ displacement \ reaction}

Explanation:

<h2><u>Displacement reaction:</u></h2>
  • A reaction in which an element displaces or replaces another element of a compound is called a displacement reaction.
<h3><u>Types:</u></h3>

There are 2 types:

<h3><u>1. Single displacement reaction:</u></h3>
  • If one element displaces 1 other element of a compound, it is called single displacement reaction.
  • <u>Example</u>:  CuSO_4 +Fe \longrightarrow \ FeSO_4 + Cu
  • Here, 1 element (Fe) displaces 1 other element (Cu) of a compound.
<h3><u>2. Double displacement reaction:</u></h3>
  • If two elements in two compounds displace one another, it is called double displacement reaction.
  • <u>Example:</u> CuSO_4+NaOH \longrightarrow Cu(OH)_2 + Na_2SO_4
  • Here, Copper and sodium both displace each other.

\rule[225]{225}{2}

4 0
1 year ago
Q 3.6: calculate the number of po43- ions present in 23.7 g of ca3(po4)2.
malfutka [58]
Moles of ca3(po4)2 = 23.7 / 310.17 =  0.076

moles of (PO4)3- = 0.076 x 2 = 0.152

now, no. of ions = 0.152 x 6.022 x 10^{23}

                          =  9.2 x 10^{22}
6 0
2 years ago
Read 2 more answers
Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu
pochemuha

Answer : The volume of CO_2 will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2

First we have to calculate the  mass of HCO_3^- in tablet.

\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g

Now we have to calculate the moles of HCO_3^-.

Molar mass of HCO_3^- = 1 + 12 + 3(16) = 61 g/mole

\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles

Now we have to calculate the moles of CO_2.

From the balanced chemical reaction, we conclude that

As, 1 mole of HCO_3^- react to give 1 mole of CO_2

So, 0.0202 mole of HCO_3^- react to give 0.0202 mole of CO_2

The moles of CO_2 = 0.0202 mole

Now we have to calculate the volume of CO_2 by using ideal gas equation.

PV=nRT

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = 37^oC=273+37=310K

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)

V=0.51411L=514.11ml

Therefore, the volume of CO_2 will be, 514.11 ml

6 0
2 years ago
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