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Marta_Voda [28]
3 years ago
6

A flask holds 3.01 x 1023 molecules of carbon dioxide. The container is holding ________

Chemistry
1 answer:
sammy [17]3 years ago
8 0
 (B), because 1.0 moles would be 6.02 x 10^23 molecules. So you have half a mole.<span>
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What are the final materials of a reaction called? Where are they located in an<br> equation?
fredd [130]

Answer:

Reactants are starting materials and are written on the left-hand side of the equation. Products are the end-result of the reaction and are written on the right-hand side of the equation.

Explanation:

4 0
3 years ago
the formula of calcium oxide is CaO. What is the formula of the ionic compound containing calium abd sulfate ions
sineoko [7]

Answer:

CaS

Explanation:

Hello!

In this case, since calcium's oxidation state when forming ionic bonds is +2 and sulfur's oxidation state when bonding those bonds is -2, for the required formula we write:

Ca^{2+}S^{2-}

Now, since they have the same charge number, we infer the ionic compound formed when they bond is calcium sulfide:

CaS

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5 0
2 years ago
Select the reagents you would use to synthesize the compounds below from benzene. Use the minimum number of steps.
iris [78.8K]

Answer:

A

C

Explanation:

For the reaction of m-bromonitrobenzene from benzene first, we need to carry out the nitration of benzene utilizing HNO3, H2SO4.  

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5 0
3 years ago
Does this graph represent an endothermic or exothermic chemical reaction? Explain your reasoning. ​
Natali [406]

Answer:

it is an exothermic reaction

Explanation:

exothermic reactions have a negative ∆H

i.e, product of the reaction is less that the reactants of the reaction

(Note : ∆H= products - reactants), that's why it's exothermic

5 0
2 years ago
A concentrated salt solution has a mass of 5.29 g for a 5.00 mL sample. What is the specific gravity of this solution
TiliK225 [7]

Answer:

\rho_s=1.07g/cc^3

Explanation:

From the question we are told that:

Mass M=5.29g

Volume V=5.00mL=>5.0cc^3

Generally the equation for Specific Gravity momentum is mathematically given by

Specific\ Gravity\ g= Density\ of\ Salt\ Solution\ \rho_s / Density\ of\ Water\ \rho_w

 g=\frac{ \rho_s} { \rho_w}

 \rho_s=\frac{ g} { \rho_w}

 \rho_s=\frac{ 5.29} { 5}

 \rho_s=1.07g/cc^3

7 0
3 years ago
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