Answer:

Explanation:
Given that:
The energy of the photon = 2.3 eV
Energy in eV can be converted to energy in J as:
1 eV = 1.60 × 10⁻¹⁹ J
So, Energy = 
Considering

Where,
h is Plank's constant having value 
c is the speed of light having value 
is the wavelength of the light being bombarded
Thus,




Also,
1 m = 10⁻⁹ nm
So,

Use Henderson Hasselbache
PH=pka+log([salt]/[acid])
Pka=-log(ka)
-log(1.4x10^-4)= 3.85
log(.83/.14)= .77
3.85+.77= 4.62
PH=4.62
Answer:
The answer to your question is 71.22 g
Explanation:
Data
Density = 19.3 g/cm³
Volume = 0.00369
mass = ?
Formula
Density = 
Solve for mass
mass = density x volume
Process
1.- Convert volume from liters to cubic centimeters
1 l ---------------- 1000 cm³
0.00369l --------- x
x = (0.00369 x 1000 ) / 1
x = 3.69 cm³
2.- Substitution
mass = 19.3 x 3.69
3.- Simplification and result
mass = 71.22 g