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HACTEHA [7]
4 years ago
6

After completing an experiment to determine gravimetrically the percentage of water in a hydrate, a student reported a value of

38 percent. The correct value for the percentage of water in the hydrate is 51 percent. Which of the following is the most likely explanation for this difference?
a) Strong initial heating caused some of the hydrate sample to splatter out b) The dehydrated sample absorbed moisture after heating c) The amount of the hydrate sample used was too small d) The crucible was not heated to constant mass before use e) Excess heating caused the dehydrated sample to decompose
Chemistry
1 answer:
SIZIF [17.4K]4 years ago
6 0

Answer:

b) The dehydrated sample absorbed moisture after heating

Explanation:

a) Strong initial heating caused some of the hydrate sample to splatter out.

This will result in a higher percent of water than the real one, because you assume in the calculation that the splattered sample was only water (which in not true).

b) The dehydrated sample absorbed moisture after heating.

Usually inorganic salts may absorbed moisture from the atmosphere so this will explain the 13% difference between calculated water percent the real content of water in the hydrate.

c) The amount of the hydrate sample used was too small.

It will create some errors but they do not create a difference of 13% difference as stated in the problem.

d) The crucible was not heated to constant mass before use.

Here the error is small.

e) Excess heating caused the dehydrated sample to decompose.

Usually the inorganic compounds are stable in the temperature range of this kind of experiments. If you have an organic compound which retain water molecules you may decompose the sample forming volatile compounds which will leave crucible so the error will be quite high.

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3 years ago
Do atoms of a specific element contain the same number of protons
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Explanation:

There are two types of element weight I think.

5 0
3 years ago
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Answer:

K = \frac {[Cr_{2}O_{7}^{2-}]}{[CrO_{4}^{2-}]^{2} \cdot [H_{3}O^{+}]^{2}}  

Explanation:  

The equilibrium constant for a given reversible aqueous reaction is defined by the product ratio of the concentrations between the products and reactants:      

                                           aA + bB ⇄ cC + dD

K = \frac {[products]^{p}}{[reactants]^{r}} = \frac {[C]^{c} \cdot [D]^{d}}{[A]^{a} \cdot [B]^{b}}  

<em>where K: is the equilibrium constant, [C] and [D]: are the product concentrations, [A] and [B]: are the reactant concentrations and a,b,c,d: are the stoichiometric coefficients from the reaction.   </em>

Therefore, based on the definition the equilibrium constant of our reaction is:    

2CrO₄²⁻(aq) + 2H₃O⁺(aq) ⇄ Cr₂O₇²⁻(aq) + 3H₂O(l)

K = \frac {[Cr_{2}O_{7}^{2-}]}{[CrO_{4}^{2-}]^{2} \cdot [H_{3}O^{+}]^{2}}  

Generally, the water concentration is omitted from the expressions.

I hope it helps you!

8 0
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The total pressure of the gas has been 11.9 atm.

The partial pressure has been the pressure exerted by the individual gas in the mixture.

According to the Dalton's law of Partial pressure, the pressure of the gas has been the sum of the partial pressure of each gas in the mixture.

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The total pressure of the gas has been 11.9 atm.

Learn more about the vapor pressure, here:

brainly.com/question/25356241

7 0
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