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3 years ago

The common name for the compound ch3ch2ch2 och2ch3 is

1 answer:

4 0

Caesium sulfate (cesium sulfate) is the inorganic compound and salt with the formula Cs2SO4. It is a white water-soluble solid that is used to prepare dense aqueous solutions for use in isopycnic (or "density-gradient") centrifugation. It is isostructural with potassium salt.

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Sulfurous acid, H2SO3, breaks down into water (H20) and sulfur dioxide (SO2).

erastovalidia [21]

Answer:

1 atom of sulfur

Explanation:

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3 years ago

In caves, dripping groundwater containing calcium bicarbonate can form stalactites and stalagmites. When the water is exposed to

bija089 [108]

A new substance is formed in this process which is an important clue to chemical change

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3 years ago

You have a cotton towel, strips of tissue paper, and an aluminum pie plate to use in an experiment. Which of the following is a

Svetradugi [14.3K]

Answer:

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Explanation:

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3 years ago

7. Write a formula for each of the following:

sergeinik [125]

Answer : The formula for each of the following is:

(a) $C_{22}H_{46}$

(b) $C_{17}H_{34}$

(c) $C_{13}H_{24}$

Explanation :

Alkanes are hydrocarbon in which the carbon atoms are connected with single covalent bonds.

The general formula of alkanes is $C_n H_{2n+2}$ where n is the number of the carbon atoms present in a molecule of alkane.

Alkenes are hydrocarbon in which the carbon atoms are connected with double covalent bonds.

The general formula of alkenes is $C_n H_{2n}$ where n is the number of the carbon atoms present in a molecule of alkene.

Alkynes are hydrocarbon in which the carbon atoms are connected with triple covalent bonds.

The general formula of alkynes is $C_n H_{2n-2}$ where n is the number of the carbon atoms present in a molecule of alkyne.

(a) An alkane with 22 carbon atoms

Putting n = 22 in the general formula of alkane, we get the formula of alkane as, $C_{22}H_{2(22)+2}$ or $C_{22}H_{46}$

(b) An alkene with 17 carbon atoms

Putting n = 17 in the general formula of alkene, we get the formula of alkene as, $C_{17}H_{2(17)}$ or $C_{17}H_{34}$

(c) An alkyne with 13 carbon atoms

Putting n = 13 in the general formula of alkyne, we get the formula of alkyne as, $C_{13}H_{2(13)-2}$ or $C_{13}H_{24}$

3 0

3 years ago

Read 2 more answers

For many purposes we can treat methane as an ideal gas at temperatures above its boiling point of . Suppose the temperature of a

Elza [17]

Answer:

The volume decreases 5.5%

Explanation:

First, the question is incomplete, you are not giving the values of the temperatures and the pressure. However, I managed to find one similar question, and the given data is the temperature is lowered from 21 °C to -8°C, and the pressure decreased by 5%. If your data is different, you should only replace your data in the procedure, and you'll get an accurate result.

Now, with this data, let's see what we can do.

If this is an ideal gas, the equation to use is:

PV = nRT

Now, we know that this gas is suffering a decrease in temperature and pressure, but the moles stay the same so:

n₁ = n₂ = n

The constant R, is the same for both conditions. The only thing that differs here is the volume, temperature, and pressure. Therefore:

P₁V₁ = nRT₁ -----> n = P₁V₁ / RT₁

Doing the same with the pressure and volume 2 we have:

n = P₂V₂ / RT₂

Equalling both expressions and solving for V₂:

P₁V₁ / RT₁ = P₂V₂ / RT₂

V₂ = P₁T₂V₁ / P₂T₁

Now, as we know that P2 is 5% decreased from P1, so P2 = 0.95P1:

V₂ = P₁T₂V₁ / 0.95P₁T₁

The values of temperature in K:

T1 = 21+273 = 294 K

T2 = -8 + 273 = 265 K

Finally, let's calculate the volume:

V₂ = 264*P₁*V₁ / 294*0.95*P₁ ----> P cancels out

V₂ = 264V₁ / 294*0.95

V₁ = 0.945V₂

With this, we can day that Volume 2 decreases.

Now the percentage change would be using the following expression:

%V = (V₁ - V₂ / V₁) * 100

Replacing the data we have:

%V = V1 - 0.945V₁ / V₁

%V = 0.055V₁ / V₁ * 100

%V = 5.5%

7 0

3 years ago