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UNO [17]
4 years ago
11

Anh measured the temperature of a pond near his house. Before he left for school, the water in the pond was 18 degrees celsius.

When he came home from school, the temperature of the pond was higher than it was in the morning. What happened to the water molecules while he was at school?
A) The molecules get closer together.
B) the molecules started moving faster.
C) The water lost its molecules.
D) The molecules became larger.
Chemistry
1 answer:
Hitman42 [59]4 years ago
3 0

As the temperature increases, B) the molecules started moving faster.

Explanation:

The temperature of a substance is a measure of the average kinetic energy of the particles in a substance. In particular, it can be found that the temperature is directly proportional to the average kinetic energy of the particles:

T\propto KE

The kinetic energy of a particle is given by

KE=\frac{1}{2}mv^2

where

m is the mass of the particle

v is its speed

This means that the higher the temperature of a substance, the greater the speed of the particles in the substance.

Therefore, if we apply this concept to this problem, we infer that as the temperature of the water in the pond gets higher, the speed of the molecules inside the water increases, which means that the molecules are moving faster.

Therefore, the correct answer is

B) the molecules started moving faster.

Learn more about temperature:

brainly.com/question/1603430

brainly.com/question/4370740

#LearnwithBrainly

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2 . O, Ni, P, G

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it takes 60 days for 1024 grams of element XY to decay to 32 grams. what is the half life of element XY
KonstantinChe [14]

Answer:

The half life of element XY is 12 days

Explanation:

Given:

Time taken for  1024 grams to decay into 32 grams  = 60 days

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The half life of element XY = ?

Solution:

The Half life is calculated by

N = N_0 (\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}

t_{\frac{1}{2}} =\frac{t}{log_{\frac{1}{2}}( \frac{N(t)}{N_0})}}

Substituting the values,

t_{\frac{1}{2}} =\frac{60}{log_{\frac{1}{2}}( \frac{32}{1024})}}

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Answer:

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