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Greeley [361]
3 years ago
11

An archaeologist discovered some charcoal at an excavation site. He sent the samples to a lab for C-14 dating, knowing that the

half-life of C-14 is approximately 5,600 years. The lab reported that the charcoal had 1/8 the amount of C-14 in it that a living sample would have. How many years old
was the charcoal?
A. 700 years
B. 1,867 years
C. 8,400 years
D. 16,800 years
E. 44,800 years
Chemistry
1 answer:
klio [65]3 years ago
7 0
Here we assume that disintegration has occur so the normal t½ formular will not be used
mathematically we..⅛×5600 =700
therefore it is about 700years option A
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D

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a radioactive nuclide that is used for geological dating has an atomic number of 19 and mass 40. what is the symbol of this nucl
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The symbol of the radioactive nuclide, given the data is ⁴⁰₁₉K

<h3>Data obtained from the question</h3>
  • Atomic number = 19
  • Mass number = 40
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<h3>How to determine the nuclide</h3>

From the question given above, the atomic number of the nuclide is 19.

Comparing the atomic number (i.e 19) of the nuclide with those in the periodic table, the nuclide is potassium with a symbol of K

<h3>How to determine the symbol of the nuclide</h3>
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  • Mass number (A) = 40
  • Name of nuclide = Potassium (K)
  • Symbol of nuclide =?

The symbol of a nuclide is given as ᴬ₂X

Where

  • A is the mass number
  • Z is the atomic number
  • X is the symbol of the element

Thus,

ᴬ₂X => ⁴⁰₁₉K

Therefore, the symbol of the nuclide is ⁴⁰₁₉K

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brainly.com/question/886387

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