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Greeley [361]
3 years ago
11

An archaeologist discovered some charcoal at an excavation site. He sent the samples to a lab for C-14 dating, knowing that the

half-life of C-14 is approximately 5,600 years. The lab reported that the charcoal had 1/8 the amount of C-14 in it that a living sample would have. How many years old
was the charcoal?
A. 700 years
B. 1,867 years
C. 8,400 years
D. 16,800 years
E. 44,800 years
Chemistry
1 answer:
klio [65]3 years ago
7 0
Here we assume that disintegration has occur so the normal t½ formular will not be used
mathematically we..⅛×5600 =700
therefore it is about 700years option A
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Answer:

0.500 mole of Xe (g) occupies 11.2 L at STP.

General Formulas and Concepts:

<u>Gas Laws</u>

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<u>Stoichiometry</u>

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Explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

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<u>Step 2: Convert</u>

  1. [DA] Set up:                                                                                                  \displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg)
  2. [DA] Evaluate:                                                                                               \displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg) = 11.2 \ \text{L Xe}

Topic: AP Chemistry

Unit: Stoichiometry

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exactly 1mol of n2o4 is placed in an empty 1 l container. if at equilibrium n2o4 is dissociated 20%, what is the value of equili
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Answer:

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Explanation:

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The equilibrium constant, K, of the reaction is:

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Replacing in K:

K = [0.4M]² / [0.8M]

<h3>K = 0.2</h3>
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