All categories

3 years ago

Can someone help me, its power functions and polynomials

Mathematics

1 answer:

maks197457 [2]3 years ago

7 0

Me! I can help you.

You might be interested in

A line passes through the point (-7,5) And has a slope of 1/2 which is another point that the line passes through

Licemer1 [7]

(9,13) would be another point that the line passes through.

5 0

3 years ago

Read 2 more answers

A square platter has sides that are 15 inches long. What is the platters perimeter?

BaLLatris [955]

The perimeter is 60 in

6 0

3 years ago

WHAT IS X³-27 SIMPLIFIED

Eduardwww [97]

Answer:

It is (x - 3)³ - 9x(3 - x)

Step-by-step explanation:

Express 27 in terms of cubes, 27 = 3³:

$= {x}^{3} - {3}^{3}$

From trinomial expansion:

${(x - y)}^{3} = (x - y)(x - y)(x - y) \\$

open first two brackets to get a quadratic equation:

${(x - y)}^{3} = ( {x}^{2} - 2xy + {y}^{2} )(x - y)$

expand further:

${(x - y)}^{3} = {x}^{3} - y {x}^{2} - 2y {x}^{2} + 2x {y}^{2} + x {y}^{2} - {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3x {y}^{2} - 3y {x}^{2} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3xy(y - x) \\ \\ { \boxed{( {x}^{3} - {y}^{3} ) = {(x - y)}^{3} - 3xy(y - x)}}$

take y to be 3, then substitute:

$( {x}^{3} - 3^3) = {(x - 3)}^{3} - 9x(3 - x)$

5 0

3 years ago

Design a Roller Coaster Portfolio

scoray [572]

1) The domain is [0,300]. The range is [0,250]

2) The slope for the initial climb is 3.57. The equation of the line is $y=3.57 x$

3) The rate of change of the second hill is -1.4

4) The rate of change of the third hill is -2.1

5) The blue hill is steeper

6) It is not a function

Step-by-step explanation:

The domain of a function is the set of values of x (the input) for which the function itself is defined.

Instead, the range of a function is the set of values of y (the output) that the function can take.

To find the domain, we have to look at the x-axis and see for which values of x the function is defined. By looking at the graph, we see that the function is defined between

x = 0 and x = 300

So, the domain is [0,300].

To find the range, we have to look at the y-axis and see for which values of y the function has an output. By looking at the graph, we see that the function has values of y between

y = 0 and x = 250

So, the range is [0,250].

The slope of a function in a certain range is given by

$m=\frac{\Delta y}{\Delta x}$

where

$\Delta y$ is the change in the y-coordinate

$\Delta x$ is the change in the x-coordinate

For the initial climb (pink line), we have:

$\Delta y = 250 - 0 = 250\\\Delta x = 70 - 0 = 70$

Therefore, the slope in this part is

$m=\frac{250}{70}=3.57$

We can now write the equation of the line in the form

y = mx + b

where b is the y-intercept: since it is zero, the line has simply the form

$y=mx \rightarrow y = 3.57 x$

Again, to calculate the slope of the hill, we use:

$m=\frac{\Delta y}{\Delta x}$

where

$\Delta y$ is the change in the y-coordinate

$\Delta x$ is the change in the x-coordinate

For the green hill, we have:

$\Delta y = 60-200 = -140$

$\Delta x = 300-200 = 100$

So the rate of change is

$m=\frac{-140}{100}=-1.4$

As before, the rate of change of the hill is

$m=\frac{\Delta y}{\Delta x}$

For the blue hill, we have:

$\Delta y = 30-230 = -300$

$\Delta x = 200-60 = 140$

So the rate of change is

$m=\frac{-300}{140}=-2.1$

To know which hill is steeper, we need to compare the magnitude of their rate of change.

In fact, both hills have rate of change negative - because we are going down along the slope. Therefore, we have to consider the magnitude of their slope.

For the green hill:

$|m| = 1.4$

For the blue hill:

$|m|=2.1$

We see that the blue hill has a greater slope (in magnitude): therefore, the blue hill is steeper.

A function is defined as a mapping (operation between two sets of variables) in which to one value of x (the input) corresponds one and only one value of y (the output).

This means that a function cannot have multiple values of y for the same x (the input).

By looking at the graph, we see that this function does not respect this criterium: in fact, we see that certain values of x give multiple values of the output, y (for instance, at x=300 the function has two values). So, this is not a function.

Learn more about functions:

brainly.com/question/3511750

brainly.com/question/8243712

brainly.com/question/8307968

#LearnwithBrainly

5 0

3 years ago

Read 2 more answers

Can u help me ASAP. i need to know how to do it step by step

12345 [234]

Answer:

19

Step-by-step explanation:

$f(x) =4x^3-8x^2+ax+b$ has a factor $2x-1$ and

when divided by $x+2$ , remainder is 20.

To find:Remainder when divided by (x-1) ?

Solution:

$2x-1$ is a factor

$2x - 1 = 0 \Rightarrow x = \frac{1}{2}$ when we put this value of x to the function, it will become 0.

i.e.

$\Rightarrow f(\dfrac{1}{2}) =0 =4\times (\dfrac{1}2)^3-8(\dfrac{1}2)^2+\dfrac{a}{2}+b=0\\\Rightarrow \dfrac{1}{2}-2+\dfrac{a}{2}+b=0\\\Rightarrow 1-4+a+2b=0\\\Rightarrow a +2b=3 ......(1)$