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Dennis_Churaev [7]
3 years ago
15

A dogsled is moving at a constant speed of 3.0 m/s in a straight line on level ground,

Physics
1 answer:
denis-greek [22]3 years ago
6 0

Answer:

0 N

Explanation:

The key for solving the problem is in the sentence "moving at a constant speed in a straight line".

In fact, this means that the velocity of the sled is constant: and therefore, that its acceleration.

Newton's second law states that:

F = ma

where

F is the net force on an object

m is its mass

a is its acceleration

In this problem, we have asserted that the acceleration of the sled is zero:

a = 0

Therefore, according to the equation above, this also means that the net force on the sled is also  zero:

F = 0 N

(This implies that there must be another force, must like the force of friction, that acts backward, in the opposite direction to the pull applied by the dogs).

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4 years ago
A student (m = 68 kg) falls freely from rest and strikes the ground. During the collision with the ground, he comes to rest in a
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5.7141 m

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mgh=\frac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}

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t = Time taken = 0.04 seconds

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v=u+at\\\Rightarrow a=\frac{v-u}{t}

From Newton's second law

F=ma\\\Rightarrow F=m\frac{v-u}{t}\\\Rightarrow 18000=68\frac{0-\sqrt{2gh}}{0.04}\\\Rightarrow \frac{18000}{68}\times 0.04=-\sqrt{2\times 9.81\times h}\\\Rightarrow 10.58823=-\sqrt{2\times 9.81\times h}

Squarring both sides

112.11061=2\times 9.81\times h\\\Rightarrow h=\frac{112.11061}{2\times 9.81}\\\Rightarrow h=5.7141\ m

The height from which the student fell is 5.7141 m

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