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3 years ago

I need help ASAP pleasee!!!

Physics

2 answers:

Vera_Pavlovna [14]3 years ago

3 0

Answer: when in doubt go with B

Explanation:

Mashcka [7]3 years ago

3 0

Answer: C

Explanation:

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If velocity is in m/s and time is in sec, what is the unit of acceleration?

WINSTONCH [101]

The unit of acceleration would be m/s² :)

6 0

2 years ago

At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coeffi

Flura [38]

The given data is incomplete. The complete question is as follows.

At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coefficient of friction was estimated to be 0.36. Use these data to determine the speed of the car when the driver slammed on (and locked) the brakes. (why does the car's mass not matter?)

Explanation:

Let us assume that v is the final velocity and u is the initial velocity of the car. Let s be the skid marks and $\mu$ be the friction coefficient and m be the mass of car.

Hence, the given data is as follows.

v = 0, s = 84 m, $\mu$ = 0.36

According to Newton's law of second motion the expression for acceleration is as follows.

F = ma

$-\mu N$ = ma

$-\mu mg$ = ma

a = $-\mu g$

Also,

$v^{2} = u^{2} + 2as$

$(0)^{2} = u^{2} + 2(-\mu g)s$

$u^{2} = 2(\mu g)s$

= $\sqrt{2(0.36)(9.81 m/s^{2})(84 m)}$

= 24.36 m/s

Thus, we can conclude that the speed of the car when the driver slammed on (and locked) the brakes is 24.36 m/s.

4 0

3 years ago

a car traveling at a speed of 72km/h is uniformly returded and comes to rest after 8 seconds if the car with the occupants has a

cricket20 [7]

Answer:

the breaking force is 12

Explanation:

7 0

3 years ago

Head restraints

KengaRu [80]

Most likely answer would be A

6 0

3 years ago

Read 2 more answers

HELP PLEASE!!! a= ? v= r=

ratelena [41]

Answer:

$a=\frac{v^2}{r}$

$v=\sqrt{a*r}$

$r=\frac{v^2}{a}$

Explanation:

This is the formula for centripetal acceleration in terms of the tangential velocity (v) and the radius of the circular motion (r). The expression for the acceleration is already given, so simply type it as shown:

$a=\frac{v^2}{r}$

For the velocity (v) multiply by "r" both sides and then use the square root to solve for v:

$a*r=v^2\\v=\sqrt{a*r}$

For the radius multiply both sides by r and then divide both sides by the acceleration (a) in order to isolate r completely:

$a*r=v^2\\r=\frac{v^2}{a}$

4 0

3 years ago