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3 years ago

URGENT

Mathematics

2 answers:

victus00 [196]3 years ago

7 0

Answer:

Step-by-step explanation:

It cannot be A or B because you already have both of your angles, and it cannot be C because the sides do not line up. By the process of elimination it will be D.

aleksklad [387]3 years ago

4 0

Answer:

Step-by-step explanation:

AAS = angle angle side

we already have the 2 angles so it cant be A or B. we need to find the equal corresponding side lengths. C is incorrect because side BC is not corresponding to side DF. therefore, it is D. sorry im bad at explaining but i hope this helped :)

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How many yards are in 42 feet

ziro4ka [17]

First you need to find how many yards is in 1 feet , so is equal = 3feet , Now you need to find one number that is multiply by 3 that is equal to 42 so that is : 14 .. I hope that this can help you :)

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3 years ago

I have a rectangle house. it is ten feet wide and 20 feet long

coldgirl [10]

Answer:

200 in all

Step-by-step explanation:

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3 years ago

two arcs of concentric circles are intercepted by the same central angle. the resulting arc length of the arc of the larger circ

Bond [772]

the complete question in the attached figure

Let
A°-----------> the same central angle

For the larger circle
length of larger circle=2*pi*r-------> 2*pi*12-----> 75.36 m

360° (full circle) has a length of------------> 75.36 m
A°-----------------------------------> 16 m
A°=(16)*360/75.36--------> A=76.43°

For the smaller circle
length of smaller circle=2pi*r-------> 2*pi*7.5-----> 47.1 m

360° (full circle) has a length of------------> 47.1 m
76.43°-----------------------------------> X
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the answer is
the length arc of the smaller circle is 10 m

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3 years ago

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inna [77]

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3 years ago

Read 2 more answers

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

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3 years ago