What is the interest of 45,580 if the interest rate is 4% per year? I need some help.

Complete this equations,( show your work).

timurjin [86]

Answer:

21 is: $\frac{4}{9}$ x + $\frac{31}{72}$

22 is: 4 $\frac{39}{44}$

23 is: $\frac{1}{4}$ x + $\frac{31}{72}$

24 is: $\frac{-2}{11}$ x + $\frac{7}{11}$

Step-by-step explanation: Hope this helps and good luck mark brainliest if u want :)

3 0

3 years ago

A Washington Post article from 2009 reported that "support for a government-run health-care plan to compete with private insurer

NemiM [27]

Answer:

a) $p_v =P(Z>1.119)=0.132$

So the p value obtained was a high low value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

b) Since we Fail to reject the null hypothesis and the 0.5 is included on the null hypothesis we would expect that 0.5 would be on the confidence interval.

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.5=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.52 - 1.96 \sqrt{\frac{0.52(1-0.52)}{783}}=0.485$

$0.52 + 1.96 \sqrt{\frac{0.52(1-0.52)}{783}}=0.555$

Step-by-step explanation:

1) Data given and notation

n=783 represent the random sample taken

X represent the people with the characteristic of interest

$\hat p=0.52$ estimated proportion of independents who oppose the plan

$p_o=0.5$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) 2) Concepts and formulas to use We need to conduct a hypothesis in order to test the claim that that a majority of Independents oppose the health care public option plan: Null hypothesis:[tex]p \leq 0.5$

Alternative hypothesis: $p > 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.52 -0.5}{\sqrt{\frac{0.5(1-0.5)}{783}}}=1.119$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>1.119)=0.132$

So the p value obtained was a high low value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Part b

Since we Fail to reject the null hypothesis and the 0.5 is included on the null hypothesis we would expect that 0.5 would be on the confidence interval.

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.5=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.52 - 1.96 \sqrt{\frac{0.52(1-0.52)}{783}}=0.485$

$0.52 + 1.96 \sqrt{\frac{0.52(1-0.52)}{783}}=0.555$

6 0

3 years ago

Find the volume of the composite solid below round your answer to the nearest tenth

gladu [14]

First find the volume of the cylinder.

The formula is: V=πr²h

Plug the numbers in the figure into the formula.

V=πr²h

V=π×3²×10

V=π×9×10

V=π90

V=282.743

Therefore, the volume of the cylinder is approximately 282.7in³

Find the volume of the rectangluar prism.

V=lwh

V=12×7×4

V=84×4

V=336

Therefore, the volume of the rectangular prism is 336in³

Add the volumes:

282.7+336=618.7

The volume of the composite solid is approximately 618.7in^3

4 0

2 years ago

Write and equation for the following description:

Taya2010 [7]

I'm sorry I don't know

8 0

3 years ago

What is 45 * 89 + 67 <55 - 56 =

gladu [14]

Answer:

False

Step-by-step explanation:

Use the order of operations

45 * 89 = 4005

4005 + 67 = 4072

55 - 56 = -1

4072 < -1

The answer is false.

4 0

3 years ago

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