Describe the motion of a ball being thrown straight up in the air in terms of kinetic and potential energy. As the ball rises up
1 answer:
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Answer:
Fnet = 14515.2 Newton
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
Where;
- Fnet is the net force.
- Fapp is the applied force.
- Fg is the force due to gravitation.
Given the following data;
Mass = 1,152 kg
Initial velocity, u = 3m/s
Final velocity, v = 17m/s
Time, t = 5 seconds
To find the magnitude of the net force;
First of all, we would determine the acceleration of the car.
Acceleration = (v-u)/t
Acceleration = (17 - 3)/5
Acceleration = 14/5
Acceleration = 2.8m/s
To find the applied force;
Fapp = mass * acceleration
Fapp = 1,152 * 2.8
Fapp = 3225.6 N
Next, we would find the force exerted on the car due to gravity.
Fg = mass * acceleration due to gravity
We know that acceleration due to gravity is equal to 9.8m/s²
Fg = 1152 * 9.8
Fg = 11289.6N
Substituting the values into the equation, we have;
Fnet = 3225.6 + 11289.6
Fnet = 14515.2 Newton
Explanation :
Simple machines makes our work easier. Lever is one of the simple machine which consists of rigid rod that is pivoted at a fixed support called as Fulcrum.
There are three classes of lever.
Class 1 : In this type of class, fulcrum is placed in between effort and load. Hence the movement of load is in reverse direction of the movement of effort. (fig 1)
Class 2 : In this type of, the load is between the effort and the fulcrum. Hence, the movement of load is in same direction as that of the effort. (fig 2)
Class 3 : In this type of lever the effort between the load and the fulcrum. Hence, both the effort and load are in same direction. (fig 3)
Hence, when the position of fulcrum is modified the effort force changes.
Answer:
0.9972 fraction of plutonium will remain after 100 years.
Explanation:
Half life of plutonium =
Let the initial mass of plutonium be =
Mass of plutonium after time of 100 years = A
Decay constant for this process =
0.9972 × 100 = 99.72 %
0.9972 fraction of plutonium will remain after 100 years.