B. Amplitude
It is the maximum distance from the equilibrium point of the pendulum.
Answer:
Kinematics
given,
time (t)=100 s, distance (s)=1 km=1000 m
V
b
=10m/s (relative speed r.p to bus)
Velocity (v)=
time
distance
=
100
1000
V
s
= velocity of scooter
V
b
→ Velocity of bus
V=V
s
−V
b
→As we know
10=V
s
−10
20=V
s
V
s
=20 m/s
Velocity with which scooterist
should chase the bus →20 m/s
Explanation:
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Answer:
304.86 metres
Explanation:
The x and y cordinates are
and
respectively
The horizontal distance travelled, 
Making t the subject, 
Since
, we substitute t with the above and obtain

Making d the subject we obtain


d=304.8584
d=304.86m
Answer:
24.3 m/s
Explanation:
1 kmh = 0.27 m/s, that makes a conversion ratio of 0.27/1kmh
x 
The "kmh" n the top and bottom cancel out. And then you just multiply the top 90 x 0.27 and the bottom 1 x 1 to get

and since its over 1 its just 24.3 m/s