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soldier1979 [14.2K]
3 years ago
14

What happens to an object after being transported to three planets in the solar system?

Physics
1 answer:
alukav5142 [94]3 years ago
6 0
The weight changes but the mass will stay the same.
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A circular test track for cars has a circumference of 3.5 km . A car travels around the track from the southernmost point to the
Marta_Voda [28]
<span>The car would have traveled exactly one-half of the circumference of the track, since it would have gone from one extreme point to its opposite extreme point. This would be equal to (3.5 / 2), or 1.75 km. The northernmost point would be 1.75km away from the southernmost point.</span>
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4 years ago
what is the magnitude of the compression forces (assumed to be horizontal) acting on both sides of the center board that is sand
Len [333]

F = normal force by each board on each side

W = weight of the board in between acting in down direction = 95.5 N

f = frictional force in upward direction by each board

\mu = coefficient of friction = 0.663

Using equilibrium of force in Upward direction

f + f = W

f = W/2

f = 95.5/2 = 47.75 N

frictional force is given as

f = \mu F

47.75 = (0.663) F

F = 72.02 N

4 0
3 years ago
Heelppp please ASAP !!!!!
Masja [62]
39.2 m/s
Since 9.8 is the acceleration of gravity times 4 gives you 39.2
4 0
3 years ago
Catherine likes the name she was given, but wishes it were shorter. She decides to start going by the new name of Cathy. It's cu
Blababa [14]

The answer would be conformity. This is a kind of social influence concerning a change in belief or conduct so one can fit in with a group. This alteration is in reply to real (physical occurrence of others) or fictional (pressure of social norms / prospects) group pressure.

3 0
3 years ago
Read 2 more answers
1.What is the kinetic energy of an object with a velocity of 7m / s and a mass of 14kg
Vlada [557]

Answer:

Explanation:

The formula for KE is

KE=\frac{1}{2}mv^2 and we fill in to solve for KE:

KE=\frac{1}{2}(14)(7.0)^2 I used 2 significant digits in the velocity because 1 isn't accurate enough. Therefore, my answer will be rounded to 2 sig fig's:

KE = 340 J (rounded from 343). And we do the exact same thing in #2:

KE=\frac{1}{2}(5.0)(5.0)^2 (Used 2sig fig's for both the mass and the velocity) to get

KE = 63 J (rounded from 62.5)

3 0
3 years ago
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