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igomit [66]
3 years ago
8

Help Plz Due Tmrw. ......​

Mathematics
2 answers:
romanna [79]3 years ago
4 0

Answer:

i´ll help here

the smallest is (-3)^0

the second smallest or biggest is 16^1/2

the biggest one is (1/27)^-1/3

Step-by-step explanation:

hope this is correct

Nastasia [14]3 years ago
4 0

Answer:

smallest: (-3) ^0

middle: (1/27) ^-1/3

largest: 16^1/2

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X^3 - x^2 + x / x^3 + 1 simplified
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I think it’s x+1x^3... not sure if this helps
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I need help with 5 and 6
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Please help me asap!
Artemon [7]

Answer:   1. ∠A= 80.75°  2. 41.79 cm^2

Step-by-step explanation:

Since, According to the sines low,

\frac{sin A}{CB} = \frac{sin C}{AB}

Here, CB= 4.1 cm,  AB = 3.3 and ∠ C = 52.6°

\frac{sin A}{4.1} = \frac{sin 52.6}{3.3}

⇒ sin A = 4.1\times\frac{sin 52.6}{3.3}

⇒  sin A =0.98699998308

⇒ A = 80.75°

2. Since, the area of the given figure = Area of the rectangle having dimension 8.3 × 4.2 + Area of the half square of radius 2.1

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4 0
3 years ago
What is the sum of the interior angles of the polygon shown below
DanielleElmas [232]

Answer:

720 degrees.

Step-by-step explanation:

The sum of the interior angles of a convex polygon with  n  sides is

180(n - 2)  degrees.

In this case,  n = 6 sides, so the angle sum is

180(6 - 2) = 180(4) = 720 degrees.

The reason this works is that if you draw a diagonal from one vertex to the others (see attached image), you get 2 fewer triangles than the number of sides.  Each triangle contains a total of 180 degrees, so the total of all the interior angles is 180(n - 2).

7 0
2 years ago
The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-
Elena-2011 [213]

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)

3 0
2 years ago
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