Answer:
Same as before.
Explanation:
we can use momentum conservation to solve the problem.
Let mass of child be m and of the sled be M. Also let both have initial velocity u.
since, child fells off on the sled it will still have same velocity of ''u''.
By momentum conservation we have,
(M + m) x u = m x u + M x v
⇒ Mu=Mv
⇒ u=v
Hence, velocity of the sled remains the same.
Answer:
No force acts on it. It will not be pushed.
Explanation:
The proton moving in the -X direction implies its velocity is in the -X direction and the magnetic field is given to be in the +X direction. So the angle between them is 180 degrees. So no force acts on the proton, since the velocity and magnetic field are anti parallel.
Magnetic force is given by the equation F = q v B sin theta where theta is the angle between the velocity and the magnetic field. This force will be a maximum if they are perpendicular to each other.
Answer:
<em>10.46m/s</em>
Explanation:
Given
Distance = 5.58m
Required
magnitude of the velocity'
Using the equation of motion expressed as
v² = u² + 2gS
v² = 0 +2(9.8)(5.58)
v² = 109.368
v= √109.368
v = 10.46m/s
<em>Hence the magnitude of the velocity of the of the chain is 10.46m/s</em>
Resistance = (voltage) / (current) . . . <== MEMORIZE THIS
Resistance = (91 volts) / (10 Amperes)
Resistance = 9.1 ohms
Answer:A
Explanation:
In R-L circuit current is given by
where i=current at any time t
R=resistance
L=Inductance
at t=0 approaches to 1
therefore
i=0
when t approaches to , approaches to zero
thus
thus we can say that initially circuit act as broken wire with zero current
and it increases exponentially with time and act as ordinary connecting wire