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Serga [27]
3 years ago
13

Luke stands on the edge of a roof throws a ball downward. It strikes the ground with 100J of kinetic energy. Luke now throws ano

ther identical ball upward with the same initial speed, and this too falls to the ground. Neglecting air resistance, the second ball hits the ground with kinetic energy of____J
A) Less than 100
B) 100
C) 200
D) More than 200
Physics
1 answer:
attashe74 [19]3 years ago
3 0
A. Less than 100 this the answer
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An ocean wave travels 10.9 m in 5.1 s. the distance between two consecutive wave crests is 4 m. what is the frequency of the wav
Jlenok [28]
The speed of the wave is given by Distance divided by time.
Speed = 10.9/5.1
            = 2.14 m/s
But; speed is also given by frequency multiplied by wavelength
Wavelength is 4 m( distance between two successive crests)
thus; 2.14 = 4 × f
          f = 2.14/4
            = 0.535 Hz
8 0
3 years ago
Calculate the frequency of each of the following wave lengths of electromagnetic radiation. Part A 488.0 nm (wavelength of argon
Drupady [299]

Answer:

A. f=6.1475*10^{14}Hz

B. f=5.9642*10^{14}Hz

Explanation:

The frequency has an inversely proportional relationship with the concept of wavelength, the greater the wavelength, the lower the frequency. For electromagnetic waves, the frequency is equal to the speed of light, divided by the wavelength.

f=\frac{c}{\lambda}

A.

f=\frac{3*10^8\frac{m}{s}}{488*10^{-9}m}\\\\f=6.1475*10^{14}Hz

B.

f=\frac{3*10^8\frac{m}{s}}{503*10^{-9}m}\\\\f=5.9642*10^{14}Hz

7 0
4 years ago
A Galilean telescope adjusted for a relaxed eye is 36.2 cm long. If the objective lens has a focal length of 39.5 cm , what is t
GuDViN [60]

Answer:

The magnification is  m =  12

Explanation:

From the question  we are told that

   The object distance is u  = 36.2 \ cm

     The focal length is  v  =  39.5 \ cm

From the lens equation we have that

         \frac{1}{f}  =  \frac{1}{u} +  \frac{1}{v}

=>     \frac{1}{v}  =  \frac{1}{f}  - \frac{1}{u}

substituting values

       \frac{1}{v}  =  \frac{1}{39.5}  - \frac{1}{36.2}

       \frac{1}{v}  =  -0.0023

=>   v =  \frac{1}{0.0023}

=>   v =-433.3 \ cm

The magnification is mathematically represented as

         m =-   \frac{v}{u}

substituting values

        m =-   \frac{-433.3}{36.2}

         m =  12

         

6 0
3 years ago
a projectile with mass m is fired with initial horizontal velocity vx from height h above level ground. which change would have
Elza [17]

Explanation:

We know that in a projectile motion time of flight

t= \sqrt{\frac{h}{4.9} }

So, we can notice that time of flight is dependent only on height from which the projectile is thrown. The more the height the more will be time of flight. So, if we increase the height the time of flight of the projectile will certainly increase.

8 0
4 years ago
Read 2 more answers
What is the charge of an ion that has 12 protons and 10 electrons? Write the ion’s symbol.
kirill [66]
The charge is 2+ as 12-10=2, meaning a positive charge of two ions
5 0
3 years ago
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